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LUCKY_DIMON [66]
2 years ago
15

If an isotope of an element has 33 neutrons and a mass number of 64, how many electrons must it have?

Chemistry
2 answers:
larisa [96]2 years ago
7 0
The mass number is the sum of the protons and neutrons
64 = #protons + #neutrons
Find the number of protons given the number of neutrons
64 = #protons + 33
#protons = 31
In a neutral element (such as this), the number of electrons equals the number of protons
#electrons = #protons
#electrons = 31
andrew-mc [135]2 years ago
6 0

Answer:

The isotope must have 31 electrons

Explanation:

  • Mass number = (number of neutrons)+(number of protons)
  • Here, mass number of element is 64 and number of neutrons is 33
  • So, number of protons i the element = (mass number)-(number of neutrons) = (64)-(33) = 31
  • Isotope of an element remain present in neutral form.
  • So, number of protons should be equal to number of electrons in that isotope. Because proton has +1 charge and electron has -1 charge
  • So, the isotope must have 31 electrons.
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What does the roman numeral stand for in copper(1) oxide should it not be copper(II) oxide
photoshop1234 [79]

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

3 0
3 years ago
Someone anyone give me tips to finish online homework because i have 30 assignments to do
MrMuchimi

Answer:

Ok! I have four tips!

Explanation:

Create A Time Table.

Gather Information For Your Online Assignments Beforehand.

Make Notes As You Read The Course Materials.

Start Doing Your Online Assignment In Advance.

6 0
3 years ago
Consider the following four structures: What is the relationship of I and II? What is the relationship of I and III? What is the
daser333 [38]

Answer:

The different structures are shown in the attachment.

I and II - structural isomers

I and III - Structural isomers

I and IV - structural isomers

II and III - structural isomers

II and IV - structural isomers

III and IV - stereoisomers

Explanation:

The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.

  • Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.
  • Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.

From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.

  • Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.
  • Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.
  • Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position
  • Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.
  • Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.

4 0
3 years ago
Balance the equations​
slavikrds [6]

4. 4 C + S8 = 4 CS2

5. H2 + O2 = H2O2 is already balanced.

6. 4 Na + O2 = 2 Na2O

7 0
3 years ago
Parallelogram PQRS is shown below. Parallelogram P Q R S. Angle P is 116 degrees. Angle R is opposite to angle P. What are the m
aliya0001 [1]

Answer:

64 degrees

Explanation:

5 0
3 years ago
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