The standard entropy for the substances are as follows:
C6H12O2(s) = -212
<span>O2(g) = -205 </span>
<span>CO2(g) = -214 </span>
<span>H2O(l) = -70
</span>
We calculate the ∆S°r<span>eaction by the expression:
</span>∆S°rxn = ∆S°products - ∆S° reactants
∆S°rxn = (212+6x205)-(6x214+6x70)
∆S°rxn = -262 J/K ------> OPTION 3
Answer:
A. AN INCREASE IN BLOOD ACIDITY NEAR THE TISSUES
B. AN INCREASE IN BLOOD TEMPERATURE NEAR THE TISSUES.
C. THE PRESENCE OF A PRESSURE GRADIENT FOR OXYGEN.
Explanation:
Metabolically active tissues need more oxygen to carry out theirs functions. They are involved during excercise and other active phsiological conditions.
There is the reduction in the amount of oxygen reaching these tissues resulting in carbon IV oxide build up, lactic acid formation and temperature increases.
The acidity of the blood near the tissues is increased due to the accumulation of carbon IV oxide in the tissues resulting into a decreased pH. This reduces the affinity of heamoglobin to oxygen in the blood near the metabollically active tissues.
There is also the increase in temperature causing rapid offload of oxygen from oxy-heamoglobin molecules.
The partial pressure of oxygen gradient also affects the rate of oxygen offload by the blood. In metabollically active tissues, the partial pressure of oxygen is reduced in the tissues causing a direct offloading of oxygen to the tissues.
Because both reactants and products continue to form. Option (c) is the answer.
Which is better
oop?
Or oof?
I personally use oof a lot more :D
