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3 years ago

What does the process of natural selection involve

Chemistry

1 answer:

Lorico [155]3 years ago

5 0

Answer:

Only the organisms best adapted to their environment tend to survive and transmit their genetic characters in increasing numbers to succeeding generations while those less adapted tend to be eliminated.

Explanation:

According to Darwin's Theory of Evolution.

Hope this helped.

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What would be the best way to measure the volume of a small ?

WITCHER [35]

You can use a graduated cylinder.

6 0

3 years ago

A chemist designs a galvanic cell that uses these two half-reactions:

Nonamiya [84]

Answer :

(a) Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$

(b) Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$

(c) $O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

(d) Yes, we have have enough information to calculate the cell voltage under standard conditions.

Explanation :

The half reaction will be:

Reaction at anode (oxidation) : $Fe^{2+}\rightarrow Fe^{3+}+e^-$ $E^0_{anode}=+0.771V$

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

To balance the electrons we are multiplying oxidation reaction by 4 and then adding both the reaction, we get:

Part (a):

Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$ $E^0_{anode}=+0.771V$

Part (b):

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

Part (c):

The balanced cell reaction will be,

$O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

Part (d):

Now we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=(1.23V)-(0.771V)=+0.459V$

For a reaction to be spontaneous, the standard electrode potential must be positive.

So, we have have enough information to calculate the cell voltage under standard conditions.

4 0

3 years ago

How many liters of hydrogen gas are required to react with 3.5" liters of oxygen gas in the following reaction? 2H2(g)+O2(g) --&

Hatshy [7]

Answer:

7 L of H₂.

Explanation:

The balanced equation for the reaction is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

1 L of O₂ required 2 L of H₂.

Finally, we shall determine the volume of H₂ required to react with 3.5 L of O₂. This can be obtained as follow:

From the balanced equation above,

1 L of O₂ required 2 L of H₂.

Therefore, 3.5 L of O₂ will require

= 3.5 × 2 = 7 L of H₂.

Thus, 7 L of H₂ is required to for the reaction.

5 0

3 years ago

Then if I have 210.1 g barium chloride with 45g potassium...how many grams of potassium chloride will I produce?

Katarina [22]

Answer:

85.8 g

Explanation:

The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...

210.1/208.233 ≈ 1.009 mol

The molar mass of K is about 39.089 g/mol, so 45 g is about ...

45/39.089 ≈ 1.1509 mol

The balanced equation seems to be ...

BaCl₂ + 2K ↔ 2KCl + Ba

This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.

The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.

The reaction produces 85.8 g of KCl.

8 0

3 years ago

Read 2 more answers

How many protons are in nitrogen

Hatshy [7]

Answer:

Explanation:

There are 7 protons in nitrogen

4 0

3 years ago

Read 2 more answers