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3 years ago

Write an equation for the graph below in slope-intercept form:

Mathematics

1 answer:

Zanzabum3 years ago

8 0

Answer: y<1x-2

Step-by-step explanation:

Find some coordinates on the line to write a slope intercept form equation for the line and turn it into inequality.

First we need to find the slope and the y-intercept. The y intercept is when x is 0 and as we can see it already indicates that the y intercept is -2 .

(0,-2)

(2,0) Use these points o the find the slope.

0- 2 = -2

-2 -0 = -2

-2/-2 = 1 The slope is one so the equation will be y = 1x - 2 But since this is not an inequality we have to change the equal to sign to an inequality sign.

Looking at the line, it is a dashed line so the inequality sign will be > or <

The painted side of the graph represents the solutions of the graph and that is all underneath the graph so the inequality will be y < 1x-2

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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Consider the quadratic function f(x) = –2x2 + 4x – 2. Find the y-intercept and the equation of the axis of symmetry.

RoseWind [281]

Answer:

The y-intercept is -2

The equation of the axis of symmetry is x = 1 ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the general form of the quadratic function

- The general form of the quadratic function is f(x) = ax² + bx + c,

where a, b , c are constant

# a is the coefficient of x²

# b is the coefficient of x

# c is the y-intercept

- The meaning of y-intercept is the graph of the function intersects

the y-axis at point (0 , c)

- The axis of symmetry of the function is a vertical line

(parallel to the y-axis) and passing through the vertex of the curve

- We can find the vertex (h , k) of the curve from a and b, where

h is the x-coordinate of the vertex and k is the y-coordinate of it

# h = -b/a and k = f(h)

- The equation of any vertical line is x = constant

- The axis of symmetry of the quadratic function passing through

the vertex then its equation is x = h

* Now lets solve the problem

∵ f(x) = -2x² + 4x - 2

∴ a = -2 , b = 4 , c = -2

∵ The y-intercept is c

∴ The y-intercept is -2

∵ h = -b/2a

∴ h = -4/2(-2) = -4/-4 = 1

∴ The equation of the axis of symmetry is x = 1

4 0

3 years ago

Exploring the graph of y equals cosine Theta

irga5000 [103]

Answer: see below

<u>Step-by-step explanation:</u>

The coordinates on the Unit Circle are (cos, sin). Since we are focused on cosine, we only need to focus on the left side of the coordinate. The cosine value (left side) will be the y-value of the function y = cos x

Use the quadrangles (angles on the axes) to represent the x-values of the function y = cos x.

Quadrangles are: 0°, 90°, 180°, 270°, 360° <em>(360° = 0°)</em>

Together, the coordinates will be as follow:

$\boxed{\begin{array}{c||c|c||c}\underline{(cos,sin)}&\underline{x=angle}&\underline{y=cosx}&\underline{\quad (x,y)\quad}\\(1,0)&0^o&1&(0^o,1)\\(0,1)&90^o&0&(90^o,0)\\(-1,0)&180^o&-1&(180^o,-1)\\(0,-1)&270^o&0&(270^o,0)\\(1,0)&360^o&1&(360^o,1)\end{array}}$

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3 years ago

A cubic meter of water has a mass of 10 kilograms. How much water is this in grams?

Cloud [144]

Each liter of water weighs 1 kg, so the weight of the water in a cubic meter is 1,000 kg.

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3 years ago

Is 8/8 greater than 3/4 ?

BlackZzzverrR [31]

8/8 is bigger than 3/4 because 8/8 is equivalent to 1 and 1 is bigger than 3/4.

3 0

3 years ago

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