If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
41 years old.
Step-by-step explanation:
Let x represent age of younger child.
We have been given that a mother has two children whose ages differ by 5 years. So the age of older child would be
.
The sum of the squares of their ages is 97. We can represent this information in an equation as:

Let us solve for x.



Divide both sides by 2:






Since age cannot be negative, therefore, age of younger child is 4 years.
Age of older child would be 
Therefore, the age of older child would be 9 years.
We have been given that the square of the mother's age can be found by writing the squares of the children's ages one after the other as a four-digit number.
Square of 4: 
Square of 9:
.
Square of mother's age: 
To find mother's age, we need to take positive square root of 1681 as:

Therefore, the mother is 41 years old.
Answer:
1/15 gal / mile if your numbers are correct
Step-by-step explanation:
1/5 / 15/4 = 1/5 * 4 / 15 = 4/60 = 1/15
Answer:
Draw an open circle on 3 and shade to the left.
Step-by-step explanation:
First, solve the inequality.
x - 6 < -3
x - 6 + 6 < -3 + 6
x < 3
The less than symbol (<) indicates that 3 is not part of the solution set. Therefore, the circle will be open.
Since the inequality indicates that x is less than 3, shade to the left of 3.
Hope that helps. :)