Mg(OH)2 is a sparingly soluble compound, in this case a base, with a solubility product, Ksp, of 5.61×10−11. It is used to contr
1 answer:
You might be interested in
There are rules to assigning conventional oxidation numbers to some elements. For those unspecified, you can solve them. This is how you solve it.
*S8. Since this is in elemental form, its oxidation number is assigned as 0.
*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.
*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.
*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.
*K₂SO₄. K is assigned with +1.
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.
<em>The S with the highest oxidation number is the one in K₂SO₄.</em>
*S8. Since this is in elemental form, its oxidation number is assigned as 0.
*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.
*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.
*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.
*K₂SO₄. K is assigned with +1.
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.
<em>The S with the highest oxidation number is the one in K₂SO₄.</em>
Explanation:
1. 2,3-dimethylhexane
2. 2,4-dimethylhexane
3. 2,5-dimethylhexane
4. 3,4-dimethylhexane
Below are the structures of the isomers.
