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irina [24]
3 years ago
10

Where is the intersection of the position and time axes located on a position-versus-time graph?

Chemistry
1 answer:
Bad White [126]3 years ago
5 0

it is located at the origin so A

hope this helped ^_^

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Write the following isotope in nuclide notation (e.g., “ 14/6C”): copper-70
Mars2501 [29]

       ⁷⁰₂₉Cu

Explanation:

Copper-70 isotope in nuclide form.

  A nuclide is designated as:                    ₙᵇX

       Where X is the symbol of the atom

      b is the mass number of the atom

     n is the atomic number

Mass number is the number of protons and neutrons in an atom. These particles makes up the bulk of the mass of an atom.

Atomic number is the number of protons in an atom. For neutral atom, it is the same as the number of electrons.

    To write Copper-70 in nuclide format:

         Symbol of Copper is Cu

         Mass number is 70

       Atomic number from periodic table is 29

                             ⁷⁰₂₉Cu

Learn more:

Atomic number brainly.com/question/5425825

#learnwithBrainly

6 0
4 years ago
3. I have 10 moles of a gas mixture. If there are 2.7 moles of hydrogen gas
UkoKoshka [18]

Answer:

there are two moles

Explanation:

6 0
4 years ago
Describe a process in which energy changes form at least two times explain how the law of conservation of energy applies to the
Dmitry_Shevchenko [17]
A pendulum.  Hold it high and it has potential energy but no kinetic energy because it is still.  As it moves down when you drop it, it changes to kinetic energy and moves faster and faster until it's at the bottom where it has no potential energy.  However, it still has momentum, so now it is changed to potential energy as it moves up the other side
5 0
4 years ago
Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2
Leokris [45]

Answer:

65.0cp

Explanation:

7 0
3 years ago
At what time will the pressure of SO₂Cl₂ decline to 0.50 its initial value? Express your answer using two significant figures.
QveST [7]

Answer: The time is 0.69/k seconds

Explanation:

The following integrated first order rate law

ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t

where

[SO₂Cl₂] concentration at time t,

[SO₂Cl₂]₀ initial concentration,

k rate constant

Therefore, the time elapsed after a certain concentration variation is given by:

t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}

We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

p_{(SO_{2}Cl_{2})}V = n_{(SO_{2}Cl_{2})}RT

[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}

In conclusion,

t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{p_{(SO_{2}Cl_{2})}} }{k}

for

p_{(SO_{2}Cl_{2})}=0.5p_{(SO_{2}Cl_{2})}_{0}

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{0.5p_{(SO_{2}Cl_{2})_{0}}} }{k}

t=\frac{ln\frac{1}{0.5} }{k}

t=\frac{ln(2)}{k}

t=\frac{0.69}{k}}

7 0
3 years ago
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