All categories

3 years ago

Where is the intersection of the position and time axes located on a position-versus-time graph?

Chemistry

1 answer:

Bad White [126]3 years ago

5 0

it is located at the origin so A

hope this helped ^_^

You might be interested in

g Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.

jarptica [38.1K]

Answer:

Following are the responses to the given choices:

Explanation:

For point a:

Using the acid and base which are strong so,

moles of $H^+$ (from $HNO_3$ )

$= 24.9\ mL \times 0.100\ M \\\\= \frac{24.9}{1000\ L} \times 0.100\ M \\\\= 2.49 \times 10^{-3} \ mol$

moles of $OH^{-}$ (from $KOH$ )

$= 25.0\ mL \times 0.100\ M \\\\= \frac{25.0}{1000 \ L} \times 0.100 \ M \\\\\= 2.50 \times 10^{-3}\ mol$

$1\ mol H^{+} \ neutralizes\ 1\ mol\ of\ OH^{-}$

So, $(2.50 \times 10^{-3} mol - 2.49 \times 10^{-3} mol)$ i.e. $1 \times 10^{-5}$ mol of $OH^-$ in excess in total volume $(24.9+25.0) \ mL = 49.9 \ mL$ i.e. concentration of $OH^- = 2 \times 10^{-4}\ M$

$p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70$

Since, $pH + pOH = 14,$

so,

$\to pH = 14- pOH = 14- 3.70 = 10.30$

For point b:

moles of $OH^-$ = from point a $= 2.50 \times 10^{-3} \ mol$

moles of $H^+$ (from $HNO_3$ ):

$= 25.1 mL \times 0.100 M\\\\ = \frac{25.1}{1000}\ L \times 0.100 \ M\\\\ = 2.51\times 10^{-3} \ mol$

1 mol $H^+$ neutralizes 1 mol of $OH^-$

So, $(2.51 \times 10^{-3}\ mol - 2.50 \times 10^{-3}\ mol)$ i.e. $1 \times 10^{-5} \ mol \ of\ H^+$ in excess in the total volume of $(25.1+25.0) \ mL = 50.1\ mL$ i.e. concentration of $H^+ = 2 \times 10^{-4}\ M$

Hence, $pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70$

6 0

3 years ago

How many electrons could have the following set of quantum numbers?.

aleksley [76]

Answer:

Explanation:

As only 2 electrons can present in an orbital, so only 2 electrons in an atom can have this set of quantum numbers.

8 0

3 years ago

Helppp ! Please :’)

Over [174]

Answer:

$\boxed{\sf \lambda \: = 1.282 \times {10}^{ 3} nm}$

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

$\frac{1}{ \lambda} = R_H {Z}^{2} \big(\frac{1}{{n_f^2}} - \frac{1}{{n_i^2}} \big)$

Where,

λ is wavelength of photon
Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in <em>Puri Sharma Pathania</em> standard book of physical chemistry &

109737 Cm-¹ according to <em>Wikipedia</em>

Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{3^2}} - \frac{1}{{5^2}} \big)$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{9}} - \frac{1}{{25}} \big)$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{25 - 9}{25 \times 9}$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{16}{225}$

$\frac{1}{ \lambda} = 7800.18 \: \: cm ^{ - 1}$

$\lambda = 1.282 \times {10}^{ - 4} cm$

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

$\lambda \: = 1.282 \times {10}^{ - 4} \times {10}^{7}$

$\lambda \: = 1.282 \times {10}^{ - 4 + 7}$

$\sf \lambda \: = 1.282 \times {10}^{ 3} nm$

$\sf \small Thanks \: for \: joining \: brainly \: community!$

4 0

2 years ago

If there are no chemical controls which can be implemented at your worksite, what can you do to protect yourself?.

Vilka [71]

If there are no chemical controls which can be implemented at your worksite than one should wear recommended PPE for protection .

PPE means personal protective equipment .
PPE at the worksite is selected to reduce the risk to health and safety .
PPE includes aprons , overalls , gloves , footwear face shields , chemical resistant glasses , and respirators .
The PPE and administrative control measures depends upon the behavior and supervision of human .
The efficacy of PPE depends entirely on the workers following the procedures and instructions appropriately .

To learn more about chemical controls please click here ,

brainly.com/question/11341397

#SPJ4

7 0

2 years ago

A break in the earth's surface between two blocks of rock that have moved past each other is called -a fault -a gauge -a plateau

devlian [24]

Correct you know your stuff

5 0

3 years ago