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love history [14]
3 years ago
15

What is the molar mass of calcium oxide

Chemistry
1 answer:
Arada [10]3 years ago
8 0
The answer is


56.0774 g/mol
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The number of protons in an atom is defined by it's
swat32

The atomic number  defines the number of protons in an atom.

6 0
3 years ago
At sea level water usually boils at 100. °C and 760. mmHg pressure. On Mt Whitney, the pressure is about 560. mmHg. At what temp
WITCHER [35]

Answer:

  91.7°C

Explanation:

We suppose you have a formula to work from. However, that is not supplied with this problem statement, so we looked one up.

The formula in the attachment is supposed to have good accuracy in the temperature range of interest. It gives vapor pressure of water in kPa, not mmHg, so we needed the conversion for that, too.

560 mmHg corresponds to about 74.66 kPa. The attached "Buck equation" formula is used to find the corresponding temperature. The exponential equation could be solved algebraically using logarithms and the quadratic formula, but we choose to find the solution graphically.

Water boils at about 91.7 °C on Mt. Whitney.

7 0
3 years ago
Organize the following atoms according to increasing number of orbitals surround the nucleus: Rubidium (Rb), Phosphorus (P), Neo
VladimirAG [237]
Hi,

Answer C
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7 0
3 years ago
Anyone know the parts of this cell? Please and thank you!
aniked [119]

Answer: A, Nucleus

B, Cell memebrane

C, vacuole

D, Chloroplast, mitocondria, amyloplast.

Explanation:

These only work if this is a plant cell which you did not specify.

4 0
3 years ago
At 850K, 65L of gas has a pressure of 450kPa. What is the volume (in liters) if the gas is cooled to 430K and the pressure decre
Novosadov [1.4K]

Answer:

V₂ =  45.53 L

Explanation:

Given data:

Initial temperature = 850 K

Initial volume = 65 L

Initial pressure = 450 KPa

Final temperature = 430 K

Final pressure = 325 KPa

Final volume = ?

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa  

V₂ = 12577500 KPa .L. K / 276250 K. KPa

V₂ =  45.53 L

8 0
3 years ago
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