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11Alexandr11 [23.1K]
3 years ago
15

The previous part could be done without using the decay equation, because the ratio of original 14C14C to present 14C14C was an

integer power of 1/2. Most problems are not so simple. To solve more general carbon-dating problems, you must first find the value of the decay constant for 14C14C, so that you can easily use the decay equation. Using the given half-life, 5730 yearsyears, find the value of the decay constant for 14C14C. Express your answer in inverse years to three significant figures. View Available Hint(s)
Chemistry
1 answer:
sukhopar [10]3 years ago
5 0

Answer: The decay constant for C14 is 0.000121years^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{5730years}=0.000121years^{-1}

The decay constant for C14 is 0.000121years^{-1}

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The molecular formula of the compound which has a molecular weight of 112.124 atomic mass units is C₆H₈O₂.

<h3>What is molecular formula?</h3>

Molecular formula of any compound tells about the composition and numbers of each entities present in that molecule.

Steps involved in the prediction of molecular formula:

  • First we predict the molar mass of given emperical formula as:

      Molar mass of C₃H₄O = 3(12) + 4(1) + 16 = 56

  • Now we divide the given mass by the calculated mass of empirical formula:

        112.124/56 = 2

  • Now we multiply the subscripts of given empirical formula by this whole number and we get:

        Molecular formula = (C₃H₄O)₂ = C₆H₈O₂

Hence correct option is (E).

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brainly.com/question/26388921

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