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Svetllana [295]
3 years ago
9

How to find the final product of Fe (II) + CI ?

Chemistry
1 answer:
pickupchik [31]3 years ago
5 0

The valency of iron (Fe) in this equation is 2

While, the valency of chlorine is 1

Therefore, we know that iron wants to give away 2 electrons to attain octet configuration, and chlorine wants to get an electron to attain octet configuration.

Also while find the products the number of atoms is similar to the oppostie valency

Fe = 1 atom , Cl = 2 atoms

Which will form FeCl₂

Happy to help :)

If you need any help pls ask

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V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}

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