Summarizing the question,
Principle(P)=$100
Rate (r)=12%=0.12
Amount (A)=3×P=$300
Time=t=?
n=no of times the interest is compouned per year=4
Then,
A=P{(1+r/n)}^(n×t)
or,300=100×{1+0.12/4}^(4×t)
or,300/100=(1+0.03)^(4×t)
or,3=1.03^(4×t)
Taking log on both sides,
log3=log[(1.03)^(4×t)]
or,log3= (4×t)×log(1.03)
or,4t=log3/log(1.03)
or,t=log3/[4×log(1.03)]
or, t=9.29175...
t=9.3 years ANS!!!
There is no mix number, it is 1/16.
There is an X intercept at x=-8
There is a y intercept at y=4 (0,4)
The recursive function is f(n + 1) = 2f(n) where f(1) = 4
<h3>How to determine the recursive function?</h3>
From the graph, we have the following values
f(1) = 4
f(2) = 8
f(3) = 12
Divide f(2) by f(1) to calculate the rate (r)
r = f(2)/f(1)
r = 8/4
r= 2
Substitute r= 2 in r = f(2)/f(1)
f(2)/f(1) = 2
Make f(2) the subject
f(2) = 2f(1)
Express 2 as 1 + 1
f(1 + 1) = 2f(1)
Express 1 as n
f(n + 1) = 2f(n)
Hence, the recursive function is f(n + 1) = 2f(n) where f(1) = 4
Read more about recursive function at:
brainly.com/question/1275192
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