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Goshia [24]
3 years ago
11

Suppose T is the transformation from ℝ2 to ℝ2 that results from a reflection over the y-axis followed by a reflection over the x

-axis. Find the matrix A that induces T.Suppose T is the transformation from ℝ2 to ℝ2 that results from a reflection over the y-axis followed by a reflection over the x-axis. Find the matrix A that induces T.Suppose T is the transformation from ℝ2 to ℝ2 that results from a reflection over the y-axis followed by a reflection over the x-axis. Find the matrix A that induces T
Mathematics
1 answer:
LenKa [72]3 years ago
8 0

<u>Answer:</u>

A = \begin{pmatrix}-1 & 0 \\0 & -1\end{pmatrix}

<u>Step-by-step explanation:</u>

Let, there be a point (x , y) in R2

After reflection on Y axis, it will be ( -x , y) and thereafter if we reflect the image over X -axis , it will be (-x , -y)

So,

we need to find out a matrix

[tex]\begin{pmatrix}a & b \\c & d\end{pmatrix}[tex]

such that,

(x , y) [tex]\begin{pmatrix}a & b \\c & d\end{pmatrix}[tex] = (-x. -y)

So, we  have the following set of equations.

ax + cy = -x ------------(1)

bx + dy= -y-----------(2)

We can get the solution (by inspection) as,

[tex]\begin{pmatrix}a & b \\c & d\end{pmatrix}[tex]

= [tex]\begin{pmatrix}-1 & 0 \\0 & -1\end{pmatrix}[tex]

So, the matrix is,

A = \begin{pmatrix}-1 & 0 \\0 & -1\end{pmatrix} (answer)

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The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

8 0
3 years ago
Do 4x and 15 + x have the same value when x is 5
Andru [333]

Answer:

They have the same value when x=5

Step-by-step explanation:

4x

Let x = 4

4*5 = 20

15+x

Let x =5

15+5 = 20

They have the same value when x=5

7 0
2 years ago
Read 2 more answers
Please help me it is easy,
Basile [38]

Answer:

i think id say it is 10.5 i might be wrong though

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Some one explain this to me
lubasha [3.4K]
7.50
25% also equals 1/4 so divide 130.00 by 4 which equals 32.50
subtract 32.50 from 130.00 which equals the cost, 97.50
97.50 minus 90$ is 7.50, therefore that is the answer
4 0
3 years ago
Review later
____ [38]
It would be 50 times because 15 divided by 3 is 5 and you just add your 0 back and get 50! hope this helps!
3 0
2 years ago
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