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sergeinik [125]
3 years ago
10

Explain why aldehydes and ketones react with a weak acid such as hydrogen cyanide but do not react with strong acids such as hcl

or h2so4 (other than being protonated by them).
Chemistry
1 answer:
sertanlavr [38]3 years ago
6 0

Answer:

The cyanide ion is a strong nucleophile.

Explanation:

Strong acids

Strong acids like hydrochloric and sulfuric acid dissociate completely in solution.

\underbrace{\hbox{HCl }}_{\hbox{strong acid}} + {\text{ H$_{2}$O }} \longrightarrow \text{H}_{3}\text{O}^{+}+ \underbrace{\hbox{Cl^{-}}}_{\hbox{weak nucleophile}}

Because they are strong acids, their conjugate bases are extremely weak bases/nucleophiles.

Thus, they can protonate the carbonyl oxygen, but the conjugate bases cannot act as nucleophiles.

Weak acids

Weak acids like HCN dissociate only slightly in solution.

\underbrace{\hbox{HCN}}_{\hbox{weak acid}} + {\text{ H$_{2}$O }} \rightleftharpoons \text{H}_{3}\text{O}^{+}+ \underbrace{\hbox{:CN^{-}}}_{\hbox{strong nucleophile}}

Because HCN is a weak acid, its conjugate base is a strong nucleophile.

Thus, it generates relatively few hydronium ions, but the cyanide ion is a strong nucleophile that can attack the partially positive carbon and form the cyanohydrin.

RCH=O + CN⁻ ⟶ RCH(CN)O⁻ ⟶ RCH(CN)OH

As the CN⁻ ions react with the aldehyde or ketone, they are removed from solution.

According to Le Châtelier's Principle, more HCN dissociates to replace the CN⁻ ions, and the reaction goes nearly to completion.

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sveticcg [70]
A) 10.0g of Iron is \frac{10.0}{55.8}=179mmol of Iron.

One mole of dihydrogen is required to form one mole of iron, hence you'll need 0.179*1.00=0.179g of dihydrogen.

B) Likewise : 2.50g of Iron is \frac{2.50}{55.8}=44.8mmol of Iron, hence we'll need 44.8*(3*16+2*55.8)=7.15g of Fe2O3.
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4 years ago
An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be . If the atom in
lara31 [8.8K]
Loses two = +2
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8 0
3 years ago
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MaRussiya [10]
Calcium reacts gently with water to give hydrogen and calcium hydroxide, which is only slightly soluble, thus slows down the reaction.

It will be assumed that hydrochloric acid used is a dilute aqueous solution.

However, calcium reacts with hydrochloric acid to give calcium chloride which is readily soluble in water, and hydrogen, being a typical reaction of relatively active metals with acids.
Ca(s) + 2HCl(aq)  -> CaCl2(aq) +H2(g) ↑ + heat

The clues that it is a chemical reaction could be:
- formation of a new substance, gaseous hydrogen
- disappearance of a metallic solid in the solution
- heat formed during the vigorous reaction.

As silver is below hydrogen in the electrochemical series, it will not be expected to react with dilute hydrocloric acid. (however, it dissolves in oxidizing acid such as nitric acid, but not displacing hydrogen as a product).

8 0
3 years ago
Draw every stereoisomer for 1-bromo-2-chloro-1,2-difluorocyclopentane. Use wedge-and-dash bonds for the substituent groups, and
Flauer [41]

Answer:

Explanation:

The objective here is mainly drawing the diagrams of every stereoisomer for 1-bromo-2-chloro-1,2-difluorocyclopentane.

Stereoisomerism is the difference of the spatial arrangement of atoms in a molecule or a compound with the same molecular formula.

For 1-bromo-2-chloro-1,2-difluorocyclopentane.

We have the stereoisomers as follows:

(1R,2S)-1-bromo-2-chloro-1,2-difluorocyclopentane.

(1S,2R)-1-bromo-2-chloro-1,2-difluorocyclopentane.

(1S,1S)-1-bromo-2-chloro-1,2-difluorocyclopentane.

(1R,1R)-1-bromo-2-chloro-1,2-difluorocyclopentane.

Their diagrams are drawn and shown in the attached file below in the order with which they are listed above.

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Answer:c

Explanation:

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