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3 years ago

The process in which a plant uses sunlight to change water and carbon dioxide into sugar and oxygen quizle?

Chemistry

2 answers:

Svetach [21]3 years ago

8 0

Answer: this process is called photosynthesis

Gwar [14]3 years ago

5 0

Answer:

This process is the photosynthesis

Explanation:

The general equation for photosynthesis is this one:

6CO₂ + 6H₂O ⇒ light ⇒ C₆H₁₂O₆ + 6O₂

It consists in two steps:

- Light reaction, where the electrons travels in the photosystems

- Calvin cycle, where, the ATP and NADPH generated in the Light reaction is used to convert CO₂ in Glyceraldehyde 3-phosphate

This is an exothermic reaction because heat is released and endergonic cause needs energy.

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Ii) During burning, elements in the coal are<br> converted to compounds called ????

elena-s [515]

Answer:

Gasification refers to the conversion of coal to a mixture of gases, including carbon monoxide, hydrogen, methane, and other hydrocarbons, depending on the conditions involved.

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3 years ago

Lipid molecules are made of long chains of hyrogen and _

Kazeer [188]

I believe the answer is carbon atoms

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3 years ago

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Solids, liquids, and gases are three common states of matter. Which of these states of matter can flow?

Mademuasel [1]

Liquid it would be liquid

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2 years ago

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Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal

Gelneren [198K]

Answer:

Option D. AlCl₃, MgC₂

Explanation:

We need to dissociate all the salts, to determine the i. (Van't Hoff factor).

The salt who has the highest value, will be the better conductor of electricity

CsCl → Cs⁺ + Cl⁻ i = 2

CaCl → Ca²⁺ + Cl⁻ i = 2

CaS → Ca²⁺ + S⁻² i = 2

Li₂S → 2Li⁺ + S⁻² i = 3

KBr → K⁺ + Br⁻ i = 2

AlCl₃ → Al³⁺ + 3Cl⁻ i = 4

MgC₂ → Mg²⁺ + 2C⁻ i = 3

KI → K⁺ + I⁻ i = 2

K₂S → 2K⁺ + S⁻² i = 3

The biggest i, is in pair D.

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3 years ago

The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i

Rus_ich [418]

Answer: a) The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process

a) concentration after 8.8 min:

$8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}$

$\log\frac{0.25}{a-x}=0.15$

$\frac{0.25}{a-x}=1.41$

$(a-x)=0.17M$

b) for concentration to decrease from 0.25M to 0.15M

$t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20$

$t=687s$

7 0

3 years ago