Density = Mass / Volume
Mass = Density * Volume
Mass = 8.96 * 5
Mass = 44.8 grams
If you are asking for the electron configuration of Ne, then the naswer is 2-8.
Balanced chemical equation is - 3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O
Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O
3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.
To learn more Balanced chemical equations about please visit -
brainly.com/question/15052184
#SPJ4
Answer:
4) It disrupts the normal excretion of solid wastes.
Answer:
25.0 g of sodium carbonate are present in 220 ml of the solution.
Explanation:
Hi there!
I have found the complete question on the web:
<em>Calculate the volume in milliliters of a 1.07 M sodium carbonate solution that contains 25.0g of sodium carbonate Na2CO3. Be sure your answer has the correct number of significant digits.</em>
First, let's find how many moles of sodium carbonate have a mass of 25.0 g.
The molar mass of Na₂CO₃ is 106 g/mol.
So, if 106 g of sodium carbonate is equal to 1 mol, then 25.0 g will be:
25.0 g · (1 mol / 106 g) = 0.236 mol Na₂CO₃
The solution contains 1.07 mol sodium carbonate in 1 liter.
So, if 1.07 mol sodium carbonate is present in 1 l solution, then, 0.236 mol will be present in:
0.236 mol · (1000 ml / 1.07 mo) = 221 ml (220 ml without any intermediate rounding).
25.0 g of sodium carbonate are present in 220 ml of the solution.