Answer:
There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride
Explanation:
x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen
37.42 % F by mass means 100 g of copper (II) fluoride contains 37.42 g of F.
So, 100 g of copper (II) fluoride contains 37.42 g of F
55.5 g of copper (II) fluoride contains 
g of F or 20.8 g of F
Hence there are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.
1]Well if the planets were removed the pray would have no food to eat, because of this the food chain would most likely die out, or the pray would need to find a new location with materials they can consume.
2]Explain how energy is transferred through food chains and food webs in an ecosystem. Energy is transferred through the separate trophic levels of a food chain or web by feeding.The first trophic level (producers) is that of plants which are examples of autotrophs – they make their own food.
Ca(C2H3O2)2
mole of calcium acetate = 24.6 / (40.1 + (2* (2*12+3*1+2*16)))
=0.156 mol
molarity = mole / volume = 0.156 / ((250cm^3/1000)dm^3) = 0.624M
Answer:
Hope this helps!
Explanation:
Meiosis is a process where a single cell divides twice to produce four cells containing half of the original amount of genetic information.
Because the tree might get struck by lightning and the tree will catch on fire leaving you to get burned
