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Doss [256]
3 years ago
10

If the pressure, volume, and temperature of a gas are known, which can most likely be found by using the ideal gas law

Chemistry
2 answers:
Alenkasestr [34]3 years ago
8 0

the ideal gas law equation is as follows

PV = nRT

where P - pressure

V - volume

n - number of moles

R - universal gas constant

T - temperature

so if the pressure, volume and temperature are already known

we are left with n and R

since R is the universal gas constant that has a known fixed value then R too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation


tatuchka [14]3 years ago
7 0

A.) the molar amount of gas

Hope it helps!


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4 years ago
What must be part of a quantitative observation?
KATRIN_1 [288]

A quantitative observation must be a measurement of some sort. (Something including numbers). Qualitative, on the other hand, is when you are using words to describe what has happened.

Explanation:

Quantitative observations are performed with devices such as rulers, balances, measured cylinders, beakers, and regulators. These results are measurable,using one or more senses to gather knowledge. information that doesn't involve numbers or measures. the process of making an understanding based on observations and previous knowledge. Quantitative investigations always involve numbers.

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3 years ago
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3 years ago
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Butter has a specific gravity of 0.86. What is the mass of 2.45 L<br> of butter?
Tema [17]

Answer:

mass of the butter is 2.107 kg

Explanation:

specific gravity = destiny of the substance / density of

the water at 4°C

0.86 = density of the butter / 1000

where density of the water is 1000 kg/m^3 at 4°C

density of the butter = 860kg/m^3

now,

density of the butter = mass of the butter / volume

860 = mass of the butter / 2.45 × 10^-3

( 1 L = 10^ -3 m^3)

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7 0
3 years ago
Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta
Sergeu [11.5K]

Answer:

The half-reaction for the oxidation of the manganese in MnCO_3(s) to MnO_2(s).:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

Explanation:

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;

Step 1: Balance all the atom beside oxygen and hydrogen atom;

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Manganese and carbon are balanced.

Step 2: Balance oxygen atom adding water on the required side:

MnCO_3+H_2O+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

6 0
3 years ago
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