Answer:
AH = 
Step-by-step explanation:
The opposite sides of a rectangle are congruent , so
GH = RA = 7
Using Pythagoras' identity in right Δ GHA
AH² + GH² = GA²
AH² + 7² = 10²
AH² + 49 = 100 ( subtract 49 from both sides )
AH² = 51 ( take the square root of both sides )
AH =
≈ 7.14 ( to 2 dec. places )
15x>200. The minimum number of hours he must work to earn at least $200 is 14 hours. Working 14 hours will allow him to receive $210. This is the minimum number of hours he can work because if he works 13 hours instead, he will only make $195, which is less than 200. 15x>200 (15x is equal to or greater than 200) x=14.
4.141304347826087
That's what I got when I did that
By applying the theory of <em>separable ordinary differential</em> equations we conclude that the solution of the <em>differential</em> equation
with y(0) = e is
.
<h3>How to solve separable differential equation</h3>
In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an <em>explicit</em> expression (y = f(x)) if possible.




If u = ㏑ y and du = dy/y, then:






And finally we get the <em>explicit</em> expression:
![\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}](https://tex.z-dn.net/?f=%5Cln%20y%20%3D%20%5Csqrt%20%5B3%5D%7B-2%5Ccdot%20x%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%2B%201%7D)
![y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}](https://tex.z-dn.net/?f=y%20%3D%20e%5E%7B%5Csqrt%20%5B3%5D%7B-2%5Ccdot%20x%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%2B1%7D%7D)
By applying the theory of <em>separable ordinary differential</em> equations we conclude that the solution of the <em>differential</em> equation
with y(0) = e is
.
To learn more on ordinary differential equations: brainly.com/question/14620493
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