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Over [174]
3 years ago
15

You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftove

r piece is long enough , you will use it in another fixture . How long will the leftover piece be ?
Mathematics
1 answer:
fgiga [73]3 years ago
7 0

Answer: 51/8 inches

Step-by-step explanation:

Since you must cut down the length of copper tubbing from 15 1/8 inches to 8 3/4 inches, the leftover piece will be:

15 1/8 - 8 3/4

Change the mixed fraction to improper fraction.

121/8 - 35/4

The LCM will be 8

( 121 - 70 )/8

51/8 or 6.375 inches

Therefore, the leftover piece will be 51/8 inches long

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3 years ago
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What is the distance between -70 and -30 on<br> a number line?<br> units
german

Answer:

I would guess 40, I could be wrong.

Step-by-step explanation:

70-30=40. So it would be 40 units away from eachother.

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3 years ago
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HELP!!!!!!!!!!!
Svetradugi [14.3K]

Using the mean concept, it is found that:

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

-----------------------

The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.

In this problem:

  • The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}
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Thus, the mean is:

M = \frac{1.25 - 1 + 2.25 + 0 - 2}{5} = 0.1

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

A similar problem is given at brainly.com/question/24787716

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3 years ago
[50 POINTS] WILL MARK BRAINLIEST!!! Please solve the whole page with work!! It will be very much appreciated and I will heart th
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Answer:

wait, it only 25 points...

Step-by-step explanation:

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2 years ago
Cards are dealt, one at a time, from a standard 52-card deck. a if the first 2 cards are both spades, what is the probability th
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So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.

Then third card being spades would be 11 / 50

Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49

Fifth card would be 9 / 48.

So the probability of next three cards being spades would be
\dfrac{11}{50}\cdot\dfrac{10}{49}\cdot\dfrac9{48}=\dfrac{33}{3920}\approx\boxed{0.00842}

Hope this helps.
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3 years ago
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