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S_A_V [24]
3 years ago
5

What is gravitational energy

Chemistry
2 answers:
Ket [755]3 years ago
5 0
Is the energy an object has due to its position above Earth, energy due to its height.
Rudik [331]3 years ago
4 0
It is energy associated with gravity or gravitational force. (Potential<span> </span>energy<span> held by an object because of its high position compared to a lower position).</span>
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Which of the following is true about oxidation-reduction reactions?
zloy xaker [14]

Answer:

the last one probably

Explanation:

6 0
3 years ago
Calculate the volume in liters of a 0.00183g / L mercury(1) chloride solution that contains 125 mg of (Hg 2 Cl 2 ) .
tatiyna

Answer: 68.3L

Explanation:

Density = Mass / Volume

Density =  0.00183 g/L

Mass = 125 mg =  0.125g

Volume =     Mass / Density  =  68.3L

6 0
3 years ago
10 points) Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, a
IceJOKER [234]

Answer:

The over all reaction :

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

Explanation:

Reduction at cathode :

Fe^{3+}(aq)+e^-\rightarrow Fe^{2+}(s)..[1]  

E^o_{Fe^{3+}/Fe^{2+}}=0.771 V

Reduction potential of Fe^{3+} to Fe^{2+}=0.771 V

Oxidation at anode:

Pb(s)\rightarrow Pb^{2+}(aq)+2e^-.[2]

E^o_{Pb^{2+}/Pb}=-0.126 V

Reduction potential of Pb^{3+} to Pb=-0.126 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=E^o_{Fe^{3+}/Fe^{2+}}-E^o_{Pb^{2+}/Pb}

=0.771 V-(-0.126 )=0.897 V

The over all reaction : 2 × [1] + [2]

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

7 0
4 years ago
Which statement goes against the kinetic theory of gases?
AURORKA [14]

the answer is c. Gas molecules will never collide with the walls of the container

8 0
4 years ago
Read 2 more answers
Balance the equation Mg(s) + O2(g) -&gt; MgO(s)​
Bess [88]

Answer:

2Mg(s) + O2 (g) -> 2MgO(g)

5 0
3 years ago
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