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Marina86 [1]
3 years ago
13

How much heat energy is required to raise the temperature of 200 grams of water from 25 degrees to 100 degrees?

Chemistry
1 answer:
Katen [24]3 years ago
5 0
You have to specify degrees Celsius or Fahrenheit?

Celsius will be 15000 <u>calories</u> or 62700 <u>joules</u>
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Which corresponds to a pressure of 1.23 atm??
Vadim26 [7]

Atmospheric pressure<span>, sometimes also called barometric pressure, is the pressure exerted by the weight of air in the </span>atmosphere of Earth<span> (or that of another planet)</span>

1 atm is equivalent to = 101325 Pa

= 760 mmHg

= 760 torr

= 1.01325 bar

So 1.23 atm is equal to

= 124629.8 Pa

= 934.8 mmHg

= 934.8 torr

<span>= 1.2462 bar</span>

6 0
3 years ago
Give 4 Economics activities associated with water​
MAXImum [283]

Answer:

For large rivers the problem is not simply a matter of deduction of consumptive use from runoff: it is more complex and the complexity is related to the changes in .

Explanation:

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3 years ago
there are tiny plants growing on rock fence after the several year . you observe something happened on the rock which of the fol
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it is moss

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3 years ago
Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
All of the following are balanced equations. State the
Advocard [28]

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Products: Na-2 Cl-2;

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c: reactants P-4 H-12 O-16

Products H-12 P-4 O-16

Explanation: since these equations are balanced the atoms on of element on the reactants side will be same as the atoms of the same element of the product side

7 0
4 years ago
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