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Lorico [155]
3 years ago
14

Need help please with these questions

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

33) $8440

34) $67,964.62

Step-by-step explanation:

33) The interest on 1 for 270 days is ...

... I = Prt = 1×0.09×(270/360) = 0.0675

so the proceeds from a loan with a face value of 1 will be

... 1 - 0.0675 = 0.9325

We want to find the face value of a loan with proceeds of $7870.30, so we need to solve the equation ...

... $7870.30 = P×0.9325

... P = $7870.30/0.9325 = $8440

34) The discount is computed from ...

... I = Prt = 70,000×0.063×(24/52) ≈ 2035.38

Then the amount Smith will pay for the T-bill is ...

... $70,000 -2035.38 = $67,964.62

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9.41666667 feet

Step-by-step explanation:

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3 years ago
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Is the binomial a factor of the polynomial nominal function?
Sedbober [7]

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

  • (x-1) - No
  • (x-3) - No
  • (x+3) - Yes
  • (x-5) - Yes
  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0
3 years ago
It is worth 50 points so please help
Vladimir [108]

Answer:

12 inches is the maximum length for each cloth because 60,48 and 72 are all multiples of 12.

you will have 5 pieces of blue cloth, 4 pieces of gold cloth and 6 pieces of white cloth.

4 0
3 years ago
Solve the equation 4n = 9
aliina [53]

Answer:

n = 9/4 = 2.250

Step-by-step explanation:

Rearrange:     4*n-(9)=0

Solve:  4n-9 = 0

     4n = 9

       n = 9/4 = 2.250

answer:     n = 9/4 = 2.250

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Given:
ludmilkaskok [199]
Segment GZ and Segment XY



I hope that this helped you!
4 0
3 years ago
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