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Andreas93 [3]
3 years ago
14

Help meeee! 3874 dkg = _____ dg

Chemistry
1 answer:
musickatia [10]3 years ago
6 0

Answer:

the answer is 387400 but I might be wrong

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A discarded spray paint can contains only a small volume of the propellant gas at a
Katena32 [7]

Answer:

1.24 × 10³ kPa

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 34.5 kPa
  • Initial volume of the can (V₁): 473 mL
  • Final pressure of the gas (P₂): ?
  • Final volume of the can (V₂): 13.16 mL

Step 2: Calculate the final pressure of the gas in the can

If we assume that the gas in the can behaves as an ideal gas and that the temperature remains constant, we can calculate the final pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁ / V₂

P₂ = 34.5 kPa × 473 mL / 13.16 mL = 1.24 × 10³ kPa

5 0
2 years ago
Which is a combination of pollutants that mix with water vapor in a city or near large highways and factories?
Valentin [98]
Me mememememememememememememememememeememememeemememememememe
8 0
3 years ago
Which 5.0-milliliter sample of NH3 will take the shape of and completely fill a closed 100.0-milliliter container?(1) NH3(s) (3)
antoniya [11.8K]
NH3(g) will take the shape of and completely fill a closed 100.0 milliliter container. 
5 0
3 years ago
In a certain experiment, 28.0 mL of 0.250 M HNO3and 53.0 mL of 0.320 M KOH are mixed. Calculate the number of moles of water for
Xelga [282]

Answer:

The number of moles of water formed in the resulting reaction is 6.03

[H+]: 37,2 M

[OH-]: 37,2 M

Explanation:

HNO3  +  KOH ----> KNO3 + H2O

First, we must discover the limiting reagent and we need to find out the moles, we use for this.

Moles that are used = Molarity / volume

HNO3 : 0,250 mol/L / 0,028L = 8,93 moles

KOH : 0,320 mol/L / 0,053L = 6,03 moles

The ratio of the reagents by stoichiometry is 1 to 1, so the limiting reagent is KOH, if I need 1 mole of nitric per mole of KOH, for every 8.93 moles I will need the same. However I have only 6.03 moles of KOH

The ratio of the reagents/products by stoichiometry is 1 to 1 so if I need 1 mol of KOH to make 1 mol of Water, 6,03 moles of KOH are used to make 6,03 moles of H2O.

The equilibrium of water is this:

2H2O ⇄ H3O+  +  OH-

2 moles of water are broken down into 1 mole of hydronium (H3O +) and 1 mole of hydroxyl (OH-)

6,03 moles of water are broken down into the half of those moles, so we have 3,015 moles of H3O+ and 3,015 moles of OH- but these moles are in 81,0 mL (the volume of the two solutions, 28 mL + 53 mL)

We must find out the moles in 1000 mL (1 L) so let's apply the rule of three.

81 mL ____ 3,015 moles

1000 mL ___ ( 1000 . 3,015) /81 = 37,2 M

7 0
2 years ago
I have a question can someone answer these questions for me please?
Kitty [74]
1. C
2. E
3. A
4. B
5. D
I hope that helps <3
8 0
2 years ago
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