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bixtya [17]
3 years ago
7

Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?

Chemistry
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

p_2=1.17atm

Explanation:

Hello!

In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm

Best regards!

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