Question

9. Batman (mass=91 kg) jumps straight down from a bridge into a boat (mass=510 kg) in which a criminal is fleeing. The velocity of the boat is initially 11 m/s. What is the velocity of the boat after Batman lands in it?

Answer 1

Answer:

V = 9.33 m/s

Explanation:

Given that,

Mass of the batsman, $m_1=91\ kg$

Mass of the boat, $m_2=510\ kg$                            

Initial speed of the boat, v = 11 m/s

Let V is the velocity of the boat after Batman lands in it. The net momentum of the system remains constant. Using the conservation of linear momentum to find it as :

$510\times 11=(91+510)V$

$V=\dfrac{510\times11}{(91+510)}$

V = 9.33 m/s

So, the velocity of the boat after Batman lands in it 9.33 m/s. Hence, this is the required solution.