Answer:
2. meiosis I only
Explanation:
During the zygotene stage of prophase-I of meiosis-I, homologous chromosomes synapse and are paired up. These paired homologous chromosomes are called bivalents. These paired homologous chromosomes align themselves at the equatorial plate of the cell during metaphase-I. Therefore, when observed through a microscope, cells are shown lined up two by two. During meiosis-II and mitosis, individual chromosomes with two sister chromatids are aligned at the cell's equator in metaphase.
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In my opinion the answer would be A.
Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type possible genotypes
Type A AA, AO
Type B BB, BO
Type AB AB
Type O OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired homozygous smooth haired
P gen SS x ss
F1 gen. Ss
phenotype: wire haired
