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Ne4ueva [31]
3 years ago
12

Find the value of x​

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer: 7?

Step-by-step explanation:

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The area of a circle is 616 m square find the radius 5 equals to 22/7 ​
astra-53 [7]

Step-by-step explanation:

here \: is \: your \: solution :  -  \\  \\ GIVEN  \:  \: -:- \\  \\  =  >  \: area \: of \: circle \:  = 616 \: m {}^{2}  \\  \\ \ =  > pi = 22  \div 7 \\  \\  =  > we \: need \: to \: find \: radius \:  \\  \\  =  > area \: of \: circle \:  = \pi \: r {}^{2}  \\  \\  =  >  \: \pi \: r {}^{2}  = 616 \: m {}^{2}  \\  \\  =  >  \: r {}^{2}  \times (22 \div 7) = 616 \\  \\  =  >  \: r {}^{2}  =( 616 \times 7) \div 22 \\  \\  =  >  \: r {  }^{2}  = 4312 \div 22 \\  \\  =  > r {}^{2}  = 196 \\  \\  =  >  \: r =  \sqrt{196}  \\  \\  =  >  \: r = 14 \: \:   \: (ANSWER✓✓✓) \\  \\ HOPE \:  IT \:  HELPS \:  YOU \: (◕ᴗ◕✿)

7 0
2 years ago
What is [(6.2x8.4) minus 9.28]
igor_vitrenko [27]
The answer is 42.8

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8 0
3 years ago
Read 2 more answers
What is 15 minutes later than 2:50
blsea [12.9K]

Answer:

3:05

I hope this helps

Step-by-step explanation:

5 0
3 years ago
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Which of the following statements are true?
Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is false.

B.  The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is true.

C. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)} is translated 2 units to the right and vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of \frac{1}{2}.. This option is true.

D. The function f(x)=\dfrac{1}{2}\sqrt{x} has the domain and the range all non-negative real values. The function  f(x)=\sqrt[3]{x} has the domain and the range all real values. So this option is false.

3 0
3 years ago
Fhghgggnghnghrrrrnhnhx
vichka [17]

Answer:

whatcha tryna accomplish here bud....

6 0
3 years ago
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