A) Draw three structures of 3 sulfur containing acids. Minimize formal charges by expanding sulfur's octet . Include any nonbond
ed electrons on sulfur only.
b) Indicate the oxidation state of sulfur in each compound. Treat sulfur as more electronegative than carbon.
I. methyl sulfenic acid
II. methyl sulfinic acid
III. methyl sulfonic acid
b) Indicate the oxidation state of sulfur in each compound. Treat sulfur as more electronegative than carbon.
I. methyl sulfenic acid
II. methyl sulfinic acid
III. methyl sulfonic acid
1 answer:
You may find the structure of compounds as well the oxidation number of sulfur in each compound written with blue color. The nonbonded electrons are represented by black dots.
Explanation:
In the methyl sulfenic acid sulfur have a oxidation number of 0, because we have +1 from carbon and -1 from hydroxil group.
In the methyl sulfinic acid sulfur have a oxidation number of +2 , because we have +1 from carbon, -1 from hydroxil group and -2 from oxygen.
In the methyl sulfonic acid sulfur have a oxidation number of +4 , because we have +1 from carbon, -1 from hydroxil group, -2 from one oxygen and -2 form the other oxygen.
Learn more about:
oxidation numbers
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