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3 years ago

Which phase has the most space between the particles? A.solid B.gas C.liquid

Chemistry

2 answers:

jonny [76]3 years ago

8 0

Answer:

B. gas

Explanation:

The particles of matter in the gaseous state are neither close together nor fixed in place. The gas expands to fill its container. Thus, a given number of particles will have the most space between them in the gas state.

Brums [2.3K]3 years ago

8 0

B) gas
hope this helps x

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In the presence of a strong acid, litmus paper exhibits a(n) _________________ color.

tino4ka555 [31]

The answer is blue!!!!!!

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3 years ago

Why are silver, lead, and mercury so special? (why do they always precipitate out and never dissolve) PLEASE BE DETAILED BUT SIM

lara [203]

Silver and lead are special elements, where silver is insoluble in all halogen anions (like AgCl, AgI, AgBr)
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3 years ago

Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III

Vlada [557]

Answer: The given amount of iron reacts with 9.0 moles of $O_2$ and produce 6.0 moles of $Fe_2O_3$

Explanation:

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

For oxygen gas:

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = $\frac{3}{4}\times 12.0=9.0mol$ of oxygen gas

For iron (III) oxide:

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = $\frac{2}{4}\times 12.0=6.0mol$ of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of $O_2$ and produce 6.0 moles of $Fe_2O_3$

5 0

3 years ago

What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?

sashaice [31]

Answer:

$\boxed {\boxed {\sf PCl_3}}$

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

22.5 g P
77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

P: 30.974 g/mol
Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. $22.5 \ g \ P * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P$