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<u>Answer:</u> The for the given reaction is
<u>Explanation:</u>
For the given chemical reaction:
Half reactions for the given cell follows:
<u>Oxidation half reaction:</u> ( × 2)
<u>Reduction half reaction:</u>
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate standard Gibbs free energy, we use the equation:
Where,
n = number of electrons transferred = 2
F = Faradays constant = 96500 C
= standard cell potential = 0.406 V
Putting values in above equation, we get:
Hence, the for the given reaction is