Answer:
Distance between them after 5 hours is 300 km.
Explanation:
From point A a vehicle leaves at 80 km / h at the same time a cyclist leaves at 20 km / h at what distance is they from each other after 5 hours.
Distance traveled by A in 5 hours = speed x time = 80 x 5 = 400 km
Distance traveled by B in 5 hours = speed x time = 20 x 5 = 100 km
The distance between them after 5 hours = 400 - 100 = 300 km
Answer:
X
Explanation:
v=u+at but t is constant so
a=v-u
for x
a=29-10
a=19
which marks the greater acceleration
Answer:
![2.72\cdot 10^{-3} m/s^2](https://tex.z-dn.net/?f=2.72%5Ccdot%2010%5E%7B-3%7D%20m%2Fs%5E2)
Explanation:
Let's start by calculating the angular velocity of the Moon. We know that the period is:
![T=27.3 d \cdot 24 \cdot 60 \cdot 60 =2.36\cdot 10^6 s](https://tex.z-dn.net/?f=T%3D27.3%20d%20%5Ccdot%2024%20%5Ccdot%2060%20%5Ccdot%2060%20%3D2.36%5Ccdot%2010%5E6%20s)
So now we can calculate its angular velocity:
![\omega=\frac{2\pi}{T}=\frac{2\pi}{(2.36\cdot 10^6)}=2.66 \cdot 10^{-6} rad/s](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7BT%7D%3D%5Cfrac%7B2%5Cpi%7D%7B%282.36%5Ccdot%2010%5E6%29%7D%3D2.66%20%5Ccdot%2010%5E%7B-6%7D%20rad%2Fs)
The centripetal acceleration is given by
![a=\omega^2 r](https://tex.z-dn.net/?f=a%3D%5Comega%5E2%20r)
where
![\omega=2.66\cdot 10^{-6}rad/s](https://tex.z-dn.net/?f=%5Comega%3D2.66%5Ccdot%2010%5E%7B-6%7Drad%2Fs)
is the radius of the orbit
Substituting,
![a=(2.66\cdot 10^{-6})^2(3.84\cdot 10^8)=2.72\cdot 10^{-3} m/s^2](https://tex.z-dn.net/?f=a%3D%282.66%5Ccdot%2010%5E%7B-6%7D%29%5E2%283.84%5Ccdot%2010%5E8%29%3D2.72%5Ccdot%2010%5E%7B-3%7D%20m%2Fs%5E2)
Well Hmm how much you tell me it’s your work lol
Answer:
![2.33\ m/s^2](https://tex.z-dn.net/?f=2.33%5C%20m%2Fs%5E2)
Explanation:
<u>Net Force
</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = m.a
Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.
The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.
The net force is Fn = 5000 N - 1500 N = 3500 N
To find the acceleration, we solve the equation for a:
![\displaystyle a=\frac{Fn}{m}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7BFn%7D%7Bm%7D)
![\displaystyle a=\frac{3500}{1500}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7B3500%7D%7B1500%7D)
![\boxed{a = 2.33\ m/s^2}](https://tex.z-dn.net/?f=%5Cboxed%7Ba%20%3D%202.33%5C%20m%2Fs%5E2%7D)
The car's acceleration is ![a = 2.33\ m/s^2](https://tex.z-dn.net/?f=a%20%3D%202.33%5C%20m%2Fs%5E2)