Question

What is the molarity of 0.50 g of Na dissolved in a 1.5 L solution?

Answer 1

Molar mass Na = 23.0 g/mol

1 mole Na ------- 23.0 g
 ? mole Na ------ 0.50 g

moles = 0.50 * 1 / 23.0

moles = 0.50 / 23.0

= 0.0217 moles of Na

Molarity = number of moles / liters solution

M = 0.0217 / 1.5

= 0.014467 M

hope this helps!

Answer 2

Answer : The molarity of solution is, 0.0145 mole/L

Solution : Given,

Mass of solute, Na= 0.50 g

Volume of solution = 1.5 L

Molar mass of Na= 23 g/mole

Molarity : It is defined as the number of moles of solute present in the one liter of solution.

Formula used :

$Molarity=\frac{w_b}{M_b\times V}$

where,

$w_b$ = mass of solute, Na

V = volume of solution in liters

$M_b$ = molar mass of solute, Na

Now put all the given values in the above formula, we get  the molarity of a solution.

$Molarity=\frac{0.50g}{23g/mole\times 1.5L}=0.0145mole/L$

Therefore, the molarity of solution is, 0.0145 mole/L