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DanielleElmas [232]
3 years ago
13

Agree or disagree The sun and stars move around earth everyday​

Chemistry
1 answer:
Mashutka [201]3 years ago
7 0
Agree definitely :P poop dance
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I need help with 2, 3, and 4 please help i will give the brainliest
Sphinxa [80]

Answer:

2=2.28*10^5

3=3.98*10^3

4=5.76*10^3

8 0
3 years ago
A large sport utility vehicle has a mass of 2600 kg.
Pepsi [2]
<span>Mass of CO2 = 225.632g</span>
4 0
3 years ago
The reaction below was carried out in an acidic solution. upper i minus, plus upper i upper o minus subscript 3 right arrow uppe
maria [59]

The reaction is an unbalanced redox reaction hence, the reaction  can be balanced by using the half-reaction method.

<h3>What is a redox reaction?</h3>

The term redox reaction refers to the reactionnin which electrons are transferred hence one specie is oxidized while the other specie is reduced.

Looking at the reation as shown, we can see that the reaction is an unbalanced redox reaction hence, the reaction  can be balanced by using the half-reaction method.

Learn more about redox reaction: brainly.com/question/13293425

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6 0
2 years ago
The pressure in car tires is often measured in pounds per square inch ( lb/in.2 ), with the recommended pressure being in the ra
Goshia [24]

when we convert 32.5 lb/in² to atmosphere, the result obtained is 2.21 atm

<h3>Conversion scale</h3>

14.6959 lb/in² = 1 atm

<h3>Data obtained from the question</h3>
  • Pressure (in lb/in²) = 32.5 lb/in²
  • Pressure (in ATM) =?

<h3>How to convert 32.5 lb/in² to atm</h3>

14.6959 lb/in² = 1 atm

Therefore

32.5 lb/in² = 32.5 / 14.6959

32.5 lb/in² = 2.21 atm

Thus, 32.5 lb/in² is equivalent to 2.21 atm

Learn more about conversion:

brainly.com/question/2139943

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4 0
1 year ago
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0
3 years ago
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