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Flura [38]
3 years ago
13

Find two consecutive even integers such that eight times the first equals seven times the second equals

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

Hence two consecutive even integers are 14 and 16

Step-by-step explanation:

Let x and x+2 be the two consecutive even integers

Then according to the given statement in the question

8x = 7(x+2)

<u>Distributive property </u>

8x=7x+14

<u>Subtraction Property of Equality</u>

8x-7x = 14+7x-7x

<u>Simplifying</u>

x = 14

So the first integer is 14 and second is:

x+2 = 14+2 = 16

Hence two consecutive even integers are 14 and 16 ..

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