Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D)
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
Answer:
( x + 2 ) and ( x - 11 )
Step-by-step explanation:
x² - 9x - 22 = 0
x² + 2x - 11x - 22 = 0
x ( x + 2 ) - 11 ( x + 2 ) = 0
( x + 2 ) ( x - 11 ) = 0
Factors of x² - 9x - 22 are ( x + 2 ) and ( x - 11 ).
Answer:
it's c
Step-by-step explanation:
there are 8 bears and 6 monkeys!
hope this helps:)
The domain of the function in this case will be for when the denominator is different from zero:
3x ^ 2- 3 = 0
3x ^ 2 = 3
x ^ 2 = 3/3
x ^ 2 = 1
x = + / - 1
Therefore the domain of this function are all reals without including x = 1 and x = -1
The appropriate algebraic equation is 2x = 3/4. To solve this for x, multiply both sides of this equation by (1/2), obtaining x = (1/2)(3/4) = 3/8 (answer)
