How could you increase the kinetic energy of a apple?

Chemistry

1 answer:

Agata [3.3K]3 years ago

8 0

By adding more nutrients to it<span />

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Predict the precipitate produced by mixing an Al(NO3)3 solution with a NaOH solution. Write the net ionic equation for the react

weqwewe [10]

Al(NO3)3(aq) + 3NaOH(s) --> Al(OH)3 (s) + 3NaNO3 (aq)

The precipitate here is Al(OH)3 (s), since the solid reactant is the precipitate in the aqueous solution. Usually, it is okay to assume in basic chemistry that the transition metal is going to be part of the compound that is the precipitate, especially in an acidic salt and a strong base reaction that we have here.

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3 years ago

Based on its chemical formula, which of the following substances is an organic compound

Tom [10]

I don't understand your question

6 0

3 years ago

Read 2 more answers

Please answer! I will mark you as brainlist!

blagie [28]

Answer:

a) no

b) no

c) yes

d) yes

Explanation:

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3 years ago

In a redox reaction, one of the reactants must release

Leviafan [203]

Redox reaction is the reduction and oxidation reaction. It is a chemical reaction that involves a transfer of electrons. It can mean loss of oxygen (oxidation) or gain of electrons (reduction). Oxydation is the process of where a sustance loses electrons, gains an oxygen atom/s, loses a hydrogen atom/s. reduction is the opposite.
In a redox reaction, one of the reactants must release electrons.

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3 years ago

"benzyl ethyl ether reacts with concentrated aqueous hi to form two initial organic products (a and b). further reaction of prod

ahrayia [7]

Answer:

See below.

Step-by-step explanation:

Ethers react with HI at high temperature to produce an alky halide and an alcohol.

R-OR' + HI ⟶ R-I + H-OR'

<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.

PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻

If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:

ROH +HI ⟶ R-I + H-OH

Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).

The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).

4 0

3 years ago