Destroying the wetlands will reduce the bay's water quality and vegetation will not grow effectively near bay as a result of which ecosystem will also destroy.
<h3>What is ecosystem?</h3>
All species and the physical environment with which they interact make up an ecosystem.
- Nutrient cycles and energy flows bind these biotic and abiotic components together.
- Photosynthesis brings energy into the system, which is absorbed into plant tissue.
As it is already mentioned that, water of the wetlands was carry nutrients which in turn was taken up by plants and vegetation, and if it will destroyed near a bay then the vegetation of that place will destroy as they will not get proper nutrients, which in turn also affects the ecosystem.
Hence destroying the wetlands will reduce the bay's water quality and vegetation will not grow effectively near bay as a result of which ecosystem will also destroy.
To know more about ecosystem, visit the below link:
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Jupiter is the biggest planet in are solar system
Answer:
2NaOH + CO2 -> Na2CO3 + H2O
1) Find the moles of each substance

2) Determine the limitting reagent

∴ Carbon dioxide is limitting as it has a smaller value.
3) multiply the limiting reagent by the mole ratio of unknown over known
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
4) Multiply the number of moles by the molar mass of the substance.
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g
Explanation:
Answer:
441.28 g Oxygen
Explanation:
- The combustion of hydrogen gives water as the product.
- The equation for the reaction is;
2H₂(g) + O₂(g) → 2H₂O(l)
Mass of hydrogen = 55.6 g
Number of moles of hydrogen
Moles = Mass/Molar mass
= 55.6 g ÷ 2.016 g/mol
= 27.8 moles
The mole ratio of Hydrogen to Oxygen is 2:1
Therefore;
Number of moles of oxygen = 27.5794 moles ÷ 2
= 13.790 moles
Mass of oxygen gas will therefore be;
Mass = Number of moles × Molar mass
Molar mass of oxygen gas is 32 g/mol
Mass = 13.790 moles × 32 g/mol
<h3> = 441.28 g</h3><h3>Alternatively:</h3>
Mass of hydrogen + mass of oxygen = Mass of water
Therefore;
Mass of oxygen = Mass of water - mass of hydrogen
= 497 g - 55.6 g
<h3> = 441.4 g </h3>