Question

3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?

Answer 1

Answer:

Option A (9.0) is the correct alternative.

Explanation:

The given values are:

Molarity,

= 1.5 M

Volume,

= 6000 mL

or,

= 6 L

As we know,

⇒ $Molarity=\frac{Moles}{Volume}$

or,

⇒ $The \ moles \ of \ NaCl=Molarity\times Volume$

By putting the values, we get

                                     $=1.5\times 6$

                                     $=9 \ mol$