The intensity of a sound describes <em>its loudness at a particular distance</em><em />
Sound intensity is factored by the ear's sensitivity to the particular frequencies contained in a sound
Sound loudness describes the strength of the ear's perception of a sound.
These two points being said, if the ear is more sensitive to a frequency, that sound will be louder to us than sounds at different frequencies that might not be as sensitive to our ears. <em>So, the more intense the sound, the louder it is ;)</em>
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Answer:
10.80
Explanation:
As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.
In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.
We can set up the ratio;
28.01 g of
l
N
2
needs
6.048 g of
l
H
2
1 g of
l
N
2
needs
6.048
28.01
g of
l
H
2
50.0 g of
l
N
2
needs
6.048
×
50.0
28.01
l
g of
l
H
2
=
10.80 g of
l
H
2
Answer:
Explanation:
<em>Given:</em>
Mass of ferous (Fe) produced = 750 gram.
<em>To find:</em>
Mass of water produced= ?
<em>Solution:</em>
<em>Molar mass of Fe is 55.84 gram/</em><em>mol</em>
Let's find out the number of moles of ferous produced.
Substituting the given data in above formula.
Now the given reaction is,
- For every 3 mole of production of Fe, 4 mole of waters are produced.
- let for 13.43 moles of Fe x moles of H2O will be produced.
now calculate the number of moles of H2O
mass of one mole of H2O is 18 gram, so we can calculate mass of 17.90 moles.
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Answer:
0.605 molal
Explanation:
molality is the amount of solute in a particular mass of solvent.
lets calculate the amount of benzene solute.
mass of benzene= 13.3g
molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol
amount of benzene= mass/molar mass
=13.3/78
=0.1705mol
molality= amount of solute/mass of solvent in kg
mass of solvent=282g=0.282kg
molality = 0.1705/0.282
=0.605 molal
Answer:
Blank 1: 1
Blank 2: 2
Blank 3: 1
Blank 4: 1
Explanation:
Assuming this is to balance the equation, write out the amount of each element you have on the reactants side and on the products side
Reactants Products
Ca 1 Ca 1
C 2 C 2
H 2 H 4
O 1 O 2
Comparing the two, we can see that hydrogen and oxygen have different amounts between reactants and products. Therefore, we need to multiply by some number to get the two equal. If we multiply the reactants by 2 we will get the correct amount in the products. So we put a 2 in front of the H₂O to signify this.
The balanced chemical reaction is
CaC₂ + 2 H₂O --> C₂H₂ + Ca(OH)₂
