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hram777 [196]
3 years ago
5

3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?

Chemistry
1 answer:
Leno4ka [110]3 years ago
7 0

Answer:

Option A (9.0) is the correct alternative.

Explanation:

The given values are:

Molarity,

= 1.5 M

Volume,

= 6000 mL

or,

= 6 L

As we know,

⇒ Molarity=\frac{Moles}{Volume}

or,

⇒ The \ moles \ of \ NaCl=Molarity\times Volume

By putting the values, we get

                                     =1.5\times 6

                                     =9 \ mol

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Answer:

The density of the ideal gas is directly proportional to its molar mass.

Explanation:

Density is a scalar quantity that is denoted by the symbol ρ (rho). It is defined as the ratio of the mass (m) of the given sample and the total volume (V) of the sample.

\rho = \frac{m}{V}                          ......equation (1)

According to the ideal gas law for ideal gas:

PV = nRT                                       ......equation (2)

Here, V is the volume of gas, P is the pressure of gas, T is the absolute temperature, R is Gas constant and n is the number of moles of gas

As we know,

The number of moles: n = \frac{m}{M}

where m is the given mass of gas and M is the molar mass of the gas

So equation (2) can be written as:

PV = \frac{m}{M}RT

⇒ PM= \frac{m}{V} RT

⇒ \frac{PM}{RT}= \frac{m}{V}             ......equation (3)

Now from equation (1) and (3), we get

\frac{PM}{RT}= \frac{m}{V} = \rho  

⇒ Density of an ideal gas: \rho = \frac{PM}{RT}  

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