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enyata [817]
3 years ago
14

What mass of chloride gas will react with 96.6g of sodium?

Chemistry
1 answer:
Oduvanchick [21]3 years ago
8 0
Molar mass :

Cl₂ =  71.0 g/mol        Na = 23.0 g/mol

<span>2 Na + Cl</span>₂<span> = 2 NaCl
</span>
2 x 23 g Na -------> 71.0 g Cl₂
96.6 g Na ----------> ?

Mass Cl₂ = ( 96.6 x 71.0 ) / ( 2 x 23 )

Mass Cl₂ = 6858.6 / 46

= 149.1 g of Cl₂

hope this helps!

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Calculate the volume of this irregular solid to the nearest cubic centimeter​
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8 cm3

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If the conjugate base of a molecule has a pkb of 1.4, what would you expect the molecule to be?
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If the conjugate base of a molecule has a pKb of 1.4, the molecule should be a Weak Acid.

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It's important to make sure you completely understand the terms of conjugate base, conjugate acid, pKb, pKa, and how they all relate. It's easy to mix up the meanings of these definitions.

Here are the two other pieces of information you need to know to correctly answer this question:

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  • Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base.

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3 0
1 year ago
The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is Questio
Sphinxa [80]

Answer:

Heating this gas to 55 °C will raise its volume to 6.87 liters.

Assumption: this gas is ideal.

Explanation:

By Charles's Law, under constant pressure the volume V of an ideal gas is proportional to its absolute temperature T (the one in degrees Kelvins.)

Alternatively, consider the ideal gas law:

\displaystyle V = \frac{n \cdot R}{P}\cdot T.

  • n is the number of moles of particles in this gas. n should be constant as long as the container does not leak.
  • R is the ideal gas constant.
  • P is the pressure on the gas. The question states that the pressure on this gas is constant.

Therefore the volume of the gas is proportional to its absolute temperature.

Either way,

V\propto T.

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}.

For the gas in this question:

  • Initial volume: V_1 = \rm 6.24\; L.

Convert the two temperatures to degrees Kelvins:

  • Initial temperature: T_1 = \rm 25.0\;\textdegree{C} = (25.0 + {\rm 273.15})\; K = 298.15\;K.
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Apply Charles's Law:

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 6.24\;L \times \frac{328.15\; K}{298.15\;K} = 6.87\;L.

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3 years ago
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