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3 years ago

What mass of chloride gas will react with 96.6g of sodium?

1 answer:

8 0

Molar mass :

Cl₂ = 71.0 g/mol Na = 23.0 g/mol

2 Na + Cl₂ = 2 NaCl

2 x 23 g Na -------> 71.0 g Cl₂
96.6 g Na ----------> ?

Mass Cl₂ = ( 96.6 x 71.0 ) / ( 2 x 23 )

Mass Cl₂ = 6858.6 / 46

= 149.1 g of Cl₂

hope this helps!

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Answer:

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Explanation:

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3 years ago

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5 0

3 years ago

A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$

and,

$\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903$

Now we have to partial pressure of $C_2HBrClF_3$ and $O_2$ .

According to the Raoult's law,

$p^o=X\times p_T$

where,

$p^o$ = partial pressure of gas

$p_T$ = total pressure of gas

$X$ = mole fraction of gas

$p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T$

$p_{C_2HBrClF_3}=0.0971\times 862torr=84torr$

and,

$p_{O_2}=X_{O_2}\times p_T$

$p_{O_2}=0.903\times 862torr=778torr$

Therefore, the partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

6 0

3 years ago

Show your work including units in your answer. Calculate the molar mass of Li4OH

lorasvet [3.4K]

Empirical formula: Li4OH
Answer:
1 mole: 44.771 g
1 gram = 0.022 mole

Explanation:

Element: Li
Percentage by mass: 62.01%
Number of atoms: 4
Mass of atom;: 6.941

Element: O
Percentage by mass: 35.74%
Number of atoms: 1
Mass of atom: 15.9994

Element: H
Percentage by mass: 2.25%
Number of atoms: 1
Mass of atom: 1.00794

4 0

3 years ago

0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of t

alina1380 [7]

Answer:

$M=6.03M$