<u>Answer:</u> Van't Hoff factor, i is <u>less</u> than expected from the formula of the compound and this <u>decreases</u> the effective concentration of particles.
<u>Explanation:</u>
Strong electrolytes are defined as the solutions which completely dissociate into their ions.
But, most of the strong electrolytes do not dissociate completely (act ideally) but remain partially undissociated into the ions. Thus, giving a lesser number of ions in the solution than expected.
This means that the Van't Hoff factor, <em>i</em> which denotes the number of ions is <u>less</u> than expected.
As fewer ions are released in the solution, the concentration of the solution is expected to <u>decrease</u>.
Hence, van't Hoff factor, i is <u>less</u> than expected from the formula of the compound and this <u>decreases</u> the effective concentration of particles.
The material on the right is a darker shade than the one on the left. Also the one on the right also is less of a block and a little more shagged
I had this same question a while back, so I may not be right, but I'm pretty sure it's D. None of the above.
No becasue a solution is only in a linear equation