Answer:
![\Phi_E=0.11\frac{N\cdot m^2}{C}](https://tex.z-dn.net/?f=%5CPhi_E%3D0.11%5Cfrac%7BN%5Ccdot%20m%5E2%7D%7BC%7D)
Explanation:
According to Gauss's Law, the electric flux of a charged sphere is the electric field multiplied by the area of the spherical surface:
![\Phi_E=EA\\\Phi_E=E(4\pi R^2)\\\Phi_E=\frac{q}{4\pi \epsilon_0 R^2}(4\pi R^2)\\\Phi_E=\frac{q}{\epsilon_0}](https://tex.z-dn.net/?f=%5CPhi_E%3DEA%5C%5C%5CPhi_E%3DE%284%5Cpi%20R%5E2%29%5C%5C%5CPhi_E%3D%5Cfrac%7Bq%7D%7B4%5Cpi%20%5Cepsilon_0%20R%5E2%7D%284%5Cpi%20R%5E2%29%5C%5C%5CPhi_E%3D%5Cfrac%7Bq%7D%7B%5Cepsilon_0%7D)
This is identical to the electric flux of a point charge located in the center of the sphere.
![\Phi_E=\frac{1*10^{-12}C}{8.85*10^{-12} \frac{C^2}{N\cdot m^2}}\\\Phi_E=0.11\frac{N\cdot m^2}{C}](https://tex.z-dn.net/?f=%5CPhi_E%3D%5Cfrac%7B1%2A10%5E%7B-12%7DC%7D%7B8.85%2A10%5E%7B-12%7D%20%5Cfrac%7BC%5E2%7D%7BN%5Ccdot%20m%5E2%7D%7D%5C%5C%5CPhi_E%3D0.11%5Cfrac%7BN%5Ccdot%20m%5E2%7D%7BC%7D)
If<span> a neutral </span>object loses<span> some </span>electrons<span>, </span>then<span> it will possess more protons</span>
i believe it is c but i could be wrong. (i’m sorry if i am)
Answer:
D. Scientists repeat their experiments just a few times to show that they can get the same results more than once and to catch any mistakes in the procedure.
Hope this helped! :)
An employee who has integrity is ____. D. trustworthy and honesty. Hope this helps!