Answer:
a) 0.1818
Step-by-step explanation:
Given that:
The odd that it'll snow tomorrow is 9 to 6
The probability that it will snow tomorrow 

= 0.6
The probability that it'll not snow tomorrow 


= 0.4
Let assume that the odd that it'll snow tomorrow is 9 to 2
The probability that it will snow tomorrow 

= 0.8181
The probability that it'll not snow tomorrow 


= 0.1818
Answer:
lol
Step-by-step explanation:
sry
Answer:
1.5871
Step-by-step explanation:
According to the Question,
- we have, 7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)
The Solution, With Basic Properties of Log.
7*log15-7*log16+6*log8-6*log3+5*log2-5*log3+log32-log25
7*1.176-7*1.204+6*0.903-6*0.477+5*0.3010-5*0.477+1.505-1.3979
on Solving, We get
1.5871
Answer:
Sample mean
Sample variance
Sample proportion
Step-by-step explanation:
We want to find

, for

.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)

.