1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KengaRu [80]
3 years ago
10

The wavelength of the red-pink line emitted by a laboratory sample of excited hydrogen is 656 nm. Taking a spectrum of a glowing

nebula, you find that the same red-pink line of hydrogen appears at 662 nm. You conclude that the nebula
A. Is 1% hotter than hydrogen in the laboratory sample.

B. Is moving towards us at about 1% the speed of light.

C. Is 1% cooler than hydrogen in the laboratory sample.

D. Is moving away from us at about 1% the speed of light
Chemistry
1 answer:
lions [1.4K]3 years ago
5 0

Answer:

Choice D) The nebula is moving away from the observer.

Explanation:

Is the emission here a result of electron transition or thermal radiation?

  • The energy difference between two atomic energy levels is discrete. As a result, emissions due to electron transition exist as discrete lines.
  • On the contrary, the thermal radiation of objects above 0 degree Kelvins exists as a continuous frequency spectrum.  

The red-pink emission here is as a line rather than a continuous spectrum. In other words, the red-pink line observed is a result of electron transition. The energy difference will be constant. That should be the same case on the earth as it is in space at the nebula.

Also, this energy difference does not depend on the temperature of the hydrogen. Only that at higher temperature, low-energy radiations will be less prominent. The wavelength will still be 656 nm when the light was emitted from the nebula.

The wavelength observed on the earth is longer than the wavelength emitted. The Doppler's effect is likely to be responsible. As the star moves away from the earth, the distance that light from the star needs to travel keep increasing. Consider two consecutive peaks from the star. When compared with the first peak, the second peak will need to travel a few more kilometers and will need a few more fractions of a second to get to the earth. It would appear to an observer on the earth that the frequency of the light is lower than it actually is. Accordingly, the wavelength will appear to be longer than it was when emitted from the star.

Conversely, the wavelength will appear shorter if the source is moving toward to observer. For this star, the wavelength appears to be longer than it really is. In other words, the star is moving away from the earth.

The ratio between the speed at which the star moves away from the earth and the speed of the light can be found using the equation: (Source: AstronomyOnline)

\displaystyle \frac{v}{c} = \frac{\Delta \lambda}{\lambda_0} \approx 0.009.

You might be interested in
Which type of bond is found between atoms of solid cobalt?
Vsevolod [243]
The answer is (3) metallic. Cobalt is a transition metal, so it can't be covalent bonds, which bond non-metals, therefore eliminating choice 1 and 2. Ionic bonds are between metals and non metals, but solid cobalt does not have a non metal, eliminating choice 4 as well. Metallic bonds are bonds between metals, therefore the answer is (3) metallic.
3 0
4 years ago
Read 2 more answers
State of oxygen at 25 degrees Celsius?
yawa3891 [41]
Gaseous, meaning <span>relating to or having the characteristics of a gas</span><span>:

</span>
6 0
3 years ago
Read 2 more answers
Problem 1: For which of the following activities might you want to hire a chemist?
Tatiana [17]
<span>Problem 1) From the given options the one that is proper of a chemist is the option B. testing a sample of water form a well. This activity belongs to the field called analytical chemistry which uses special techniques (instruments and processes) to study (separate, identify and quantify matter).
Problem 2) The only of the given procedures that involves a physical change in one substance is the option D. grinding chalk into a fine powder. In this process the molecules remain being the same (same atoms bonded in the number and way).</span>
3 0
3 years ago
Calculate the mass (in g) of 2.60 x 10^23 molecules of PbSO 4. The molar mass of PbSO 4 is 303.27 g/mol.
Feliz [49]

Explanation:

djdjdjdjdjdjdudujeudbndy no su dinero eydjd

djdjdjdjdjdjdudujeudbndy no es el quedóhajqp venga usted decide si me para el lunes m

[14/10 12:55 p. m.] Vicky Acpo je je je

<h3>[14/10 1oppho q</h3>

[15/10 8:15 a. m.]p t...

8 0
3 years ago
Which of the following describe the medium of a wave?
Anastaziya [24]

Answer: Water is the material an ocean wave moves through.

Explanation: An ocean wave and a sound wave are very similar because the water acts as the medium. The waves travel through the water just like a sound wave would travel through the medium.

7 0
3 years ago
Other questions:
  • At 10°c one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure. what is the henry's law constant of cl2
    6·1 answer
  • Krypton is named after the Greek word that means “secret.” Which explains why krypton was most likely given this name
    12·2 answers
  • Determine the poh of a solution with a ph of 5.00
    13·1 answer
  • A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 94.0 percent pure. How many grams are needed to prepare 0.45 L
    8·1 answer
  • What is the molar mass of carbon dioxide CO2​
    5·2 answers
  • Be sure to answer all parts. consider the combustion of butane gas: c4h10(g) + 13 2 o2(g) → 4co2(g) + 5h2o(g) (a) predict the si
    12·1 answer
  • What happens when you put sugar into vinegar
    15·1 answer
  • Explain why living things can be considered a renewable recourse
    7·2 answers
  • What volume would 32.0g of NO¹² gas occupy at 3.12 ATM and 18.0°c? What volume would 32.0 g of nitrogen oxide gas occupy at 3.12
    15·1 answer
  • Using tongs place the 250 mL beaker on hot plate
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!