All categories

3 years ago

If 638.44g CuSO4 reacts with 240.0g NaOH, which is the limiting reactant?

2 answers:

4 0

CuSO₄ + 2NaOH → Cu(OH)₂ + Na₂SO₄

M(CuSO₄)=159.61 g/mol
m(CuSO₄)=638.44 g
n(CuSO₄)=m(CuSO₄)/M(CuSO₄)
n(CuSO₄)=638.44/159.61= 4.00 mol

M(NaOH)=40.00 g/mol
m(NaOH)=240.0 g
n(NaOH)=m(NaOH)/M(NaOH)
n(NaOH)=240.0/40.00= 6.00 mol

on the reaction equation
CuSO₄ : NaOH = 1 : 2

in practice
CuSO₄ : NaOH = 4 : 6 = 1 : 1.5 ⇒ NaOH is the limiting reactant

Blizzard [7]3 years ago

3 0

Answer:

NaOH is the limiting reactant

Explanation:

Considering the chemiacl reaction :

CuSO₄ + 2NaOH → Cu(OH)₂ + Na₂SO₄

Molar Mass CuSO₄ = 159 g/mol

Molar mass NaOH = 40 g/mol

Due to stoichiometry :

159 g CuSO₄ = 80 g NaOH

Then: 638.44 g CuSO₄ should react with 321.23 g NaOH, but we have 240.o g of NaOH, so this last is the limiting reactant

You might be interested in

In one to two sentences, explain a similarity and difference between the particles in liquid water at 100 c and the particles in

mojhsa [17]

Answer:

The particle theory is used to explain the properties of solids, liquids and gases. The strength of bonds (attractive forces) between particles is different in all three states.

Explanation:

6 0

2 years ago

For the hypothetical reaction: A + B ---> 2C, write an expression that relates the disappearance of A and B to the appearance

forsale [732]

Answer:

Rate expression has been given below

Explanation:

According to the given equation, 1 molecule of A reacts with 1 molecule of B and produces 2 molecules of B at a time.

So, rate of disappearance of both A and B are one half of rate of appearance of B

Hence rate expression can be represented as:

$Rate=\frac{-\Delta [A]}{\Delta t}=\frac{-\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}$

where $\frac{-\Delta [A]}{\Delta t}$ is rate of disappearance of A, $\frac{-\Delta [B]}{\Delta t}$ is rate of disappearance of B and $\frac{\Delta [C]}{\Delta t}$ rate of appearance of C

8 0

3 years ago

How many miles of C are in 32.6 g of C2H6

sammy [17]

32.6 grams divided by the molar mass of C2H6, which is 18.0584g/mol = 1.8 moles of C2H6.

As there are two carbon atoms per C2H6, we must multiply the number of moles of C2H6 by 2 to get the number of moles of Carbon which is 3.6 moles.
The answer is 3.6 moles.

Hope this helps.

(Sorry for previously incorrect answer)

5 0

3 years ago

Convert .004569g to mg

algol [13]

Answer:

4.569 mg

:)))))))))))))))

4 0

3 years ago

Read 2 more answers

Why is it good practice to perform a mixed melting point determination at two different ratios of unknown to known materials in

My name is Ann [436]

The melting point of a particular compound is fixed and it is an important identification of an unknown compound. The practice to determine the melting point of an unknown material In different ratio with a known material is important to get the exact melting point of the unknown material. In different ratio the melting point of the unknown material will be fixed as the melting point of a pure material doesn't depend on the ratio in which they are mixed with other material. To get the exact melting point it is always good to get the melting point twice in different ratio.

6 0

3 years ago