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Irina-Kira [14]
3 years ago
15

What phenomenon is most responsible for ocean layers?

Chemistry
2 answers:
igomit [66]3 years ago
7 0

Answer:

precipitations

Explanation:

bcoz of water

vova2212 [387]3 years ago
3 0
Precipitations , is the most respionsible for ocean layers
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Many different processes, both natural and human-caused, can release carbon dioxide into the atmosphere. Which of the following
inn [45]

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carbon dioxide is added to the atmosphere naturally when organisms respire or decompose,  

Explanation:

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3 years ago
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The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product str
iren2701 [21]

Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

C2H4 + HBr ------------------------> C2H5Br.

The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.

So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.

So, if we have 100 mol/s ;

C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.

Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

So, 100/158.7 × 30.5 = 192.2.

Also the feed composition in HBr and C2H4 is;

HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.

Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)

Therefore, the fraction conversion is;

8 0
2 years ago
Identify these reactions
olga2289 [7]

Answer:

NaNO" (and any subsequent words) was ignored because we limit queries to 32 words.

8 0
2 years ago
9. At equilibrium a 2 L vessel contains 0.360
klio [65]

Answer:

Ke = 34570.707

Explanation:

  • H2(g) + Br2(g) → 2 HBr(g)

equilibrium constant (Ke):

⇒ Ke = [HBr]² / [Br2] [H2]

∴ [HBr] = (37.0 mol) / (2 L) = 18.5 mol/L

∴ [Br2] = (0.110 mol) / (2 L) = 0.055 mol/L

∴ [H2] = (0.360 mol) / (2 L) = 0.18 mol/L

⇒ Ke = (18.5 mol/L)² / (0.055 mol/L)(0.18 mol/L)

⇒ Ke = 34570.707

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3 years ago
What is "change" when we are talking about natural and physical systems?
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D: is the anwser that your looking for

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