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Talja [164]
3 years ago
8

Consider the following reversible reaction. What is the equilibrium constant expression for the given system?

Chemistry
2 answers:
ElenaW [278]3 years ago
6 0
The correct answer is A
ladessa [460]3 years ago
3 0
The question is incomplete. Complete question is attached below
..........................................................................................................................

Answer: 
Equilibrium constant (K) is defined as the ratio of concentration of product to concentration of reactant.

For the reaction:  2H2O(g)    ↔     2H2(g)      +       O2(g)

Equlibrium constant = \frac{[H_2]^2[O_2]}{[H_20]^2}

[ ] bracket in above expression indicates concentration.

  

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A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the ca
BaLLatris [955]

Answer: The density of the liquid is 1.10g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of the unknown liquid  = 938 grams

Volume of the unknown liquid = 0.852L=852cm^3  (1L=1000cm^3

Putting in the values we get:

Density=\frac{938g}{852cm^3}

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8 0
3 years ago
Which best describes the three general groups of elements?
Alex73 [517]

Answer:

D

Explanation:

3 0
3 years ago
The reaction rate is k[Ce4+][Mn2+] for the following reaction: 2Ce4+(aq) + Tl+(aq) + Mn2+(aq) → 2Ce3+(aq) + Tl3+(aq) + Mn2+(aq W
sdas [7]

Answer:

Manganese (II) ion, Mn²⁺

Explanation:

Hello,

In this case, given the overall reaction:

2Ce^{4+}(aq) + Tl^+(aq) + Mn^{2+}(aq) \rightarrow 2Ce^{3+}(aq) + Tl^{3+}(aq) + Mn^{2+}(aq)

Thus, since manganese (II) ion, Mn²⁺ is both at the reactant and products, we infer it is catalyst, since catalysts are firstly consumed but finally regenerated once the reaction has gone to completion. Moreover, since inner steps are needed to obtain it, we can infer that the given rate law corresponds to the slowest step that is related with the initial collisions between Ce⁴⁺ and Mn²⁺

Best regards.

8 0
4 years ago
How many grams of magnesium chloride can be produced if we react 32.50 g Mg with 32.50 g HCl
daser333 [38]
First, you will have to write out and balance the equation, so:

Because we’re looking at a single element reacting with an acid, we know that the reaction must be a single replacement.

Mg + HCl —-> MgCl2 + H2

We use H2, because hydrogen can only exist by itself when covalently bonded to itself, in a diatomic state.
Mg has an oxidation state of +2, while Cl has an oxidation state of -1. Therefore, you need 2 Cl to cancel the charge fully.

Now it needs to be balanced, so you get:

Mg + 2HCl —-> MgCl2 + H2

Now we have molar ratios to do our conversions

So we’ll use stoichiometry to find the theoretical yield for both reactants, and whichever one is the LEAST is the answer.

(32.5g Mg) (1mol/24.3g) (1mol MgCl2/1 mol Mg) (95.3g/1 mol MgCl2) = 127.5g

(32.5g HCl) (1mol/36.5) (1mol MgCl2/2mol HCl) (95.3g/1 mol MgCl2) = 42.4g

So, you will get 42.4 g of MgCl2
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4 years ago
How do we get more energy from the sun?
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