Consider the following reversible reaction. What is the equilibrium constant expression for the given system?
2 answers:
The question is incomplete. Complete question is attached below
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Answer:
Equilibrium constant (K) is defined as the ratio of concentration of product to concentration of reactant.
For the reaction: 2H2O(g) ↔ 2H2(g) + O2(g)
Equlibrium constant =![\frac{[H_2]^2[O_2]}{[H_20]^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_20%5D%5E2%7D%20)
[ ] bracket in above expression indicates concentration.
..........................................................................................................................
Answer:
Equilibrium constant (K) is defined as the ratio of concentration of product to concentration of reactant.
For the reaction: 2H2O(g) ↔ 2H2(g) + O2(g)
Equlibrium constant =
[ ] bracket in above expression indicates concentration.
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The rate law equation for Ozone reaction
r=k[O][O₂]
<h3>Further explanation</h3>Given
Reaction of Ozone :.
O(g) + O2(g) → O3(g)
Required
the rate law equation
Solution
The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants
For reaction
aA + bB ⇒ C + D
The rate law can be formulated:
where
r = reaction rate, M / s
k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹
a = reaction order to A
b = reaction order to B
[A] = [B] = concentration of substances
So for Ozone reaction, the rate law (first orde for both O and O₂) :
Molecular mass of C₂H₄ is,
M = 2×12 + 4×1 g/mol
M = 28 g/mol
Moles of C₂H₄ in 5.6 g of C₂H₄ :
n = 5.6/28 mol
n = 0.2 mol
Now, 1 mol of C₂H₄ contains 2 moles of carbon.
So, number of moles of carbon are :
n = 0.4 mol
We know, 1 mol of any atom contains 6.022 × 10²³ atoms.
So, number of carbon atoms are :
Hence, this is the required solution.