Question

PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!

Answer 1

$h(x)=20e^{kx}$

a. If $h(1)=20$, then $20=20e^k\implies e^k=1\implies k=0$.

b. If $h(1)=40$, then $40=20e^k\implies e^k=2\implies k=\ln2$, so that $2k+1=2\ln2+1$.

c. If $h(1)=10$, then $10=20e^k\implies e^k=\dfrac12\implies k=-\ln2$, so that $k-3=-\ln2-3$.