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Greeley [361]
3 years ago
9

If there is 126 calories in 3/4 cup of milk. How many calories in 1/2 cup of milk?

Mathematics
1 answer:
solong [7]3 years ago
7 0
126/3 = 42 calories per 1/4 cup. This 2 x 42 calories (2 quarters = 1/2 cup) = 84 calories.
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Shanna attends school for 1 week longer than 3/4 of the year. How many weeks in a year does Shanna attend school?
lorasvet [3.4K]

Answer:

48 weeks

Step-by-step explanation:

Theres 4 weeks in a month and times that by 12 and you get your answer, Hope this helps !

6 0
3 years ago
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What is greater 0.83 or 8.3
Grace [21]
8.3 is 10 times 0.83 so it is greater by a factor of 10
3 0
3 years ago
On a map, 1 inch equals 7.4 miles. Two houses are 1.5 inches apart on the map.
Art [367]

Answer:

half of 7.4 is 3.7 so the houses are 3.7 miles apart.

8 0
3 years ago
what is the distance between the points (4, 5) and (10, 13) on a coordinte plane a. 12 units b. 8 units c. 10 units d. 14 units
qaws [65]

Answer:

<h2>10 units</h2>

Option C is the correct option

Step-by-step explanation:

Let the points be A and B

A ( 4 , 5 ) ------> ( x1 , y1 )

B ( 10 , 13 ) ------> ( x2 , y2 )

Now, let's find the distance between these points:

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }

plug the values

= \:  \sqrt{(10 - 4) ^{2} +  {(13 - 5)}^{2}  }

Calculate the difference

=  \sqrt{ {(6)}^{2} +  {(8)}^{2}  }

Evaluate the power

=  \sqrt{36 + 64}

Add the numbers

=  \sqrt{100}

Write the number in exponential form with. base of 10

=  \sqrt{ {(10)}^{2} }

Reduce the index of the radical and exponent with 2

= 10 \: units

Hope this helps..

Best regards!!

7 0
3 years ago
The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 h
DaniilM [7]

Answer:

Probability that a battery will last more than 19 hours is 0.0668.

Step-by-step explanation:

We are given that the lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.

<em>Let X = lifetime of a battery in a certain application</em>

So, X ~ N(\mu=16,\sigma^{2} =2^{2})

The z-score probability distribution for normal distribution is given by;

               Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean lifetime = 16 hours

            \sigma = standard deviation = 2 hours

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a battery will last more than 19 hours is given by = P(X > 19 hours)

  P(X > 19) = P( \frac{  X -\mu}{\sigma} > \frac{19-16}{2} ) = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                              = 1 - 0.9332 = 0.0668

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 in the z table which has an area of 0.9332.</em>

Hence, the probability that a battery will last more than 19 hours is 0.0668.

5 0
3 years ago
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