How many grams of ammonia (NH3) will produce
300 grams of N2?
4NH3 + 6NO → 5N2 + 6H2O
1 answer:
Molar mass
NH3 = 17 g/mol
N2 = 28 g/mol
4 NH3 + 6 NO = 5 N2 + 6 H2O
4 x 17 g NH3 ------------ 5 x 28 g N2
?? g NH3 --------------- 300 g N2
300 x 4 x 17 / 5 x 28 =
20400 / 140 => 145.71 g of NH3
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