How many grams of ammonia (NH3) will produce 300 grams of N2? 4NH3 + 6NO → 5N2 + 6H2O

1 answer:

6 0

Molar mass

NH3 = 17 g/mol
N2 = 28 g/mol

4 NH3 + 6 NO = 5 N2 + 6 H2O

4 x 17 g NH3 ------------ 5 x 28 g N2
?? g NH3 --------------- 300 g N2

300 x 4 x 17 / 5 x 28 =

20400 / 140 => 145.71 g of NH3

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