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3 years ago

NaCl + H2SO4 ---> Na2SO4 + HCl Balance the double replacement chemical reaction.

Chemistry

2 answers:

Andrei [34K]3 years ago

5 0

Answer:

The balanced equation is:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + 2 HCl

Explanation:

For balance the chemical equation, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

Left side: 1 sodium Na, 1 chlorine Cl, 2 hydrogen, 1 sulfur S and 4 oxygen.

Right side: 2 sodium Na, 1 chlorine Cl, 1 hydrogen, 1 sulfur S and 4 oxygen.

The coefficients of each molecule below indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction. So, in this case, since all the coefficients are 1, the quantity of each element on each side of the reaction is maintained.

Since the amount of sodium Na is different on each side of the reaction, the equation will be balanced as follows:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + HCl

Now you have:

Left side: 2*1=2 sodium Na, 2*1=2 chlorine Cl, 2 hydrogen, 1 sulfur S and 4 oxygen.

Right side: 2 sodium Na, 1 chlorine Cl, 1 hydrogen, 1 sulfur S and 4 oxygen.

Since the amount of chlorine Cl is different on each side of the reaction, the equation will be balanced as follows:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + 2 HCl

Now you have:

Left side: 2*1=2 sodium Na, 2*1=2 chlorine Cl, 2 hydrogen, 1 sulfur S and 4 oxygen.

Right side: 2 sodium Na, 2*1=2 chlorine Cl, 2*1=2 hydrogen, 1 sulfur S and 4 oxygen.

Note that you finally get the same amount of each element on each side of the reaction. So the balanced equation is:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + 2 HCl

vlada-n [284]3 years ago

4 0

Answer:

2NaCl + H2SO4 ----> Na2SO4 + 2HCl

Explanation:

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Kool-aid is a mixture.

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3 years ago

Read 2 more answers

2 NaCL + CaO = CaCL2 + Na2O

Naily [24]

222 grams of calcium chloride is produced.

<h3>Explanation:</h3>

The mole concept and the chemical equation are very much closely related with each other. In the chemical reaction, the compounds or elements in both sides are balanced according to the number of atoms of each side of the reaction. So from there we can easily find the amount of reactant reacts to produce desired product.

Here we can see that 2 moles of sodium chloride produces 1 mole of calcium chloride.

So, 4 moles of sodium chloride will produce 2 moles of calcium chloride.

Now, atomic weight of calcium =40.

Atomic weight of chlorine =35.5.

So,the molecular weight of calcium chloride = $40+ 35.5\times2$

=111.

It means, 1 mole of calcium chloride weighs 111 grams.

So 2 moles of calcium chloride weighs $111\times2$ grams = 222 grams.

7 0

4 years ago

What mass, in grams, of CO2 and H2O is formed from 2.55 mol of propane?

oksian1 [2.3K]

Answer:

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

Explanation:

In this case, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Being the molar mass of each compound:

C₃H₈: 44 g/mole
O₂: 16 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

Then, by stoichiometry, the following quantities of mass participate in the reaction:

C₃H₈: 1 mole* 44 g/mole= 44 grams
O₂: 5 moles* 16 g/mole= 80 grams
CO₂: 3 moles* 44 g/mole= 132 grams
H₂O: 4 moles* 18 g/mole= 72 grams

So you can apply the following rules of three:

If by stoichiometry 1 mole of C₃H₈ forms 132 grams of CO₂, 2.55 moles of C₃H₈ how much mass of CO₂ will it form?

$mass of CO_{2} =\frac{2.55 moles of C_{3} H_{8}*132 gramsof CO_{2} }{ 1 mole of C_{3} H_{8}}$

mass of CO₂= 336.6 grams

If by stoichiometry 1 mole of C₃H₈ forms 72 grams of H₂O, 2.55 moles of C₃H₈ how much mass of H₂O will it form?

$mass of H_{2}O =\frac{2.55 moles of C_{3} H_{8}*72 gramsof H_{2}O }{ 1 mole of C_{3} H_{8}}$

mass of H₂O= 183.6 grams

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

3 0

3 years ago

What is the molarity of a KF(aq) solution containing 3.0 mol of KF in 2.00L of solution?

sergeinik [125]

Answer : The molarity of $KF$ in the solution is 1.5 M.

Explanation : Given,

Moles of $KF$ = 3.0 mol

Volume of solution = 2.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M$

Therefore, the molarity of $KF$ in the solution is 1.5 M.

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