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Tcecarenko [31]
3 years ago
15

NaCl + H2SO4 ---> Na2SO4 + HCl Balance the double replacement chemical reaction.

Chemistry
2 answers:
Andrei [34K]3 years ago
5 0

Answer:

The balanced equation is:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + 2 HCl

Explanation:

For balance the chemical equation, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

Left side: 1 sodium Na, 1  chlorine Cl, 2 hydrogen, 1 sulfur S and 4 oxygen.

Right side: 2 sodium Na, 1  chlorine Cl, 1 hydrogen, 1 sulfur S and 4 oxygen.

The coefficients of each molecule below indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction. So,  in this case, since all the coefficients are 1, the quantity of each element on each side of the reaction is maintained.

Since the amount of sodium Na is different on each side of the reaction, the equation will be balanced as follows:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + HCl

Now you have:

Left side: 2*1=2 sodium Na, 2*1=2  chlorine Cl, 2 hydrogen, 1 sulfur S and 4 oxygen.

Right side: 2 sodium Na, 1  chlorine Cl, 1 hydrogen, 1 sulfur S and 4 oxygen.

Since the amount of chlorine Cl is different on each side of the reaction, the equation will be balanced as follows:

2 NaCl + H₂SO₄ ---> Na₂SO₄ + 2 HCl

Now you have:

Left side: 2*1=2 sodium Na, 2*1=2  chlorine Cl, 2 hydrogen, 1 sulfur S and 4 oxygen.

Right side: 2 sodium Na, 2*1=2  chlorine Cl, 2*1=2 hydrogen, 1 sulfur S and 4 oxygen.

Note that you finally get the same amount of each element on each side of the reaction. So<u><em> the balanced equation is:</em></u>

<u><em>2 NaCl + H₂SO₄ ---> Na₂SO₄ + 2 HCl</em></u>

vlada-n [284]3 years ago
4 0

Answer:

2NaCl + H2SO4 ----> Na2SO4 + 2HCl

Explanation:

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<h3>Answer:</h3>

        NH₃ > NH₄NO₃ > (NH₄)₂HPO₄ > (NH₄)₂SO₄ > KNO₃ > (NH₄)H₂PO₄

<h3>Soution:</h3>

In (NH₄)₂HPO₄:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of (NH₄)₂HPO₄  =  132.06 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)₂HPO₄ × 100

Mass %age  =  28 g.mol⁻¹ / 132.06 g.mol⁻¹ × 100

Mass %age  =  21.20 %

In (NH₄)₂SO₄:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of (NH₄)₂SO₄  =  132.14 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)₂SO₄ × 100

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Molar Mass of KNO₃  =  101.10 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of KNO₃ × 100

Mass %age  =  14 g.mol⁻¹ / 101.10 g.mol⁻¹ × 100

Mass %age  =  13.84 %

In (NH₄)H₂PO₄:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of (NH₄)H₂PO₄  =  115.03 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)H₂PO₄ × 100

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Molar Mass of NH₃  =  132.14 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of NH₃ × 100

Mass %age  =  14 g.mol⁻¹ / 17.03 g.mol⁻¹ × 100

Mass %age  =  82.20 %

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Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

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Mass %age  =  Mass of N / M.Mass of NH₄NO₃ × 100

Mass %age  =  28 g.mol⁻¹ / 80.04 g.mol⁻¹ × 100

Mass %age  =  34.98 %

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