2. A cell with few energy needs would most

Chemistry

1 answer:

sattari [20]1 year ago

5 0

A Cell with few energy needs would most likely contain a small number of Mitochondria.

All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
They transform glucose into ATP, a chemical with a huge energy storage capacity.
Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
Vacuoles are typically tiny and aid in the sequestration of waste.
The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.

Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.

Learn more about cell organelles here:

brainly.com/question/13408297

#SPJ9

You might be interested in

When a scientist shares her findings with other scientists she is

finlep [7]

Answer:

communicating results

Explanation:

5 0

3 years ago

Read 2 more answers

What substance is acting as the Brønsted-Lowry base in the forward reaction below? H2O + HCI ----> H3O+ CI-

yarga [219]

H2O is the Bronsted-Lowry base because it accepts the hydrogen ion to become H3O after the reaction is complete.

6 0

2 years ago

A compound with molecular formula C5H10O2 has the following 1H NMR spectrum: 1.15 (t, 3H), 1.25 (t, 3H), 2.33 (q, 2H), 4.13 (q,

Vilka [71]

Answer:

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE = C - (H/2) - (X/2) + (N/2) +1

Where

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, $C_5H_{10}O_2$

DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

$-OCH_2CH_3$ .

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate