No because they have their full octet. They are full and don't need to bond with any other atoms. The full atoms that are happy are the noble gases.
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Answer:
<u><em>80 micro henry</em></u>
Explanation:
the inductance of inductors connected in series is calculated by L= L₁+L₂+L₃+L₄= 20+20+20+20= 80 micro henry
HNO3 and H2SO4 are Arrhenius acids which will increase the concentration of H+ when dissolved in water.
KOH and Ca(OH)2 are Arrhenius bases that increase the concentration of OH- when dissociated in water.
Answer:
b. + 1.01 V
Explanation:
Sn(s) ⇒ Sn2+ + 2e⁻ Eox = 0.14 V
Ag₊ + e⁻⇒ Ered = 0.80 V
_______________________________
Sn(s) + Ag⁺(aq) ⇒ Sn2⁺(aq) + Ag(s) Eºcell = 0.14 V + 0.80 V = 0.94 V
This problem is solved by using the Nernst equation:
Ecell = Eºcell - (0.0592 / n) log Q
since we are not at standard condition given that the concentrations are not at 1 M. So we will calculate Q first
Q = ( Sn²⁺ ) / ( Ag⁺) = 0.022/2.7 = 0.0081
Ecell = 0.94 V -(0.0592/2) x log (0.0081) = 1.00 V
It’s d
I Did this myself and was right