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Burka [1]
3 years ago
12

Chloe wants to cut a 37 in. piece of ribbon into three pieces. The second piece is to be 2 in. longer than the first, and the th

ird piece is to be 3 in. longer than the second. How long will each of the pieces be?
Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0

1st piece = x

2nd piece = x+2

3rd piece = x+2+3 = x+5

37 = x +x+2 + x+5 =

37 = 3x+7

30=3x

x = 30/3 = 10

 1st piece = 10 inches

 2nd piece = 10+2 = 12 inches

 3rd piece = 10+5 = 15 inches

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Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3

Side 2 and side 3 are the longer two congruent sides

Add up the three sides and set them equal to the given perimeter of 33. Solve for x

(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
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If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
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3 years ago
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CaHeK987 [17]

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Now we need to find the Least common multiple of the denominators in order to find our common denominator, which in this case is 6. 33/6 already has a denominator of 6, so we do not need to do anything to it. To give a denominator of 6 to 7/3, however, we must multiply by 2, giving us this:

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To turn this back into a mixed number, we divide 19 by 6, which gives us 3 with a remainder of 1. Therefore, our answer is 3 1/6. This is an equivalent fraction to the fourth answer, 3 3/18.

HTH :)

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